Whenever you see an ‘N’, ‘S’, or ‘P’ followed by a bunch of oxygens you know you have a

Arsenate (AsO43-) is structurally and chemically similar to inorganic phosphate (PO43-), and many enzymes that act on phosphate

Lapatulllka [165]

Answer:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

Explanation:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

4 0

3 years ago

What mass of Cu(s) is electroplated by running 24.5A of current through a Cu2+(aq)solution for 4.00 h?Express your answer to thr

Masja [62]

Answer: 116 g of copper

Explanation:

$Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes = 24.5A

t= time in seconds = 4.00 hr = $4.00\times 3600s=14400s$ (1hr=3600s)

$Q=24.5A\times 14400s=352800C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500C=193000C$ of electricity deposits 63.5 g of copper.

352800 C of electricity deposits = $\frac{63.5}{193000}\times 352800=116g$ of copper.

Thus 116 g of Cu(s) is electroplated by running 24.5A of current

Thus remaining in solution = (0.1-0.003)=0.097moles

8 0

2 years ago

A gas mixture contains the following gases with the mole fractions indicated: nitrogen (0.21), oxygen (0.16), carbon dioxide (0.

alukav5142 [94]

Answer:

Mole fraction Ar = 0.31

Explanation:

Remember that the sum of the mole fractions in a mixture of gases = 1

Mole fraction = Moles from a gas / Total moles

Mole fraction N₂+ Mole fraction O₂+ Mole fraction SO₂+ Mole fraction CO₂ + Mole fraction Ar = 1

N₂ = 0.21

O₂= 0.16

CO₂ = 0.23

SO₂ = 0.09

Mole fraction Ar = 1 - 0.21 - 0.16 - 0.23 - 0.09

Mole fraction Ar = 0.31

4 0

3 years ago

How many significant figures does 0.0006510 of have?

arsen [322]

It has 4 significant figures. If you see the Zero after the one decimal point you don’t count that and instead just started at 6

7 0

3 years ago

Read 2 more answers

Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each

Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0

3 years ago