Answer:
f = 80 flutter/ second
T= 0.0125 sec
Explanation:
Given data:
Fluttering of wings = 4800 time per minute
Frequency of wings = ?
Period for one wing in sec = ?
Solution:
There are 60 seconds in one minute, thus frequency of wings
4800/60 = 80 flutter per second
Period:
T = 1/f
T = 1/80
T= 0.0125 sec
Answer:
D. ![K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%5B%5Ctext%7BNO%7D_%7B2%7D%5E%7B-%7D%5D%7D%7B%5B%5Ctext%7BHNO%7D_%7B2%7D%5D%7D)
Explanation:
The general form of an equilibrium constant expression is
![K = \frac{[\text{Products}]}{[\text{Reactants}]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5B%5Ctext%7BProducts%7D%5D%7D%7B%5B%5Ctext%7BReactants%7D%5D%7D)
In the equilibrium
HNO₂ ⇌ H⁺ + NO₂⁻
The products are H⁺ and NO₂⁻, and the reactant is HNO₂.
∴ ![K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%5B%5Ctext%7BNO%7D_%7B2%7D%5E%7B-%7D%5D%7D%7B%5B%5Ctext%7BHNO%7D_%7B2%7D%5D%7D)
Answer:
(a) Perchloric acid (HClO₄)
(b) Nitric acid (HNO₃)
(c) Bromous acid (HBrO₂)
(d) Phosphoric Acid (H₃PO₄)
Explanation:
Acids are the species which furnish hydrogen ions in the solution. The other specie produced with the hydrogen ion is called its conjugate base.
Thus,
(a) Perchlorate (ClO₄⁻) ion:
The acid that furnish perchlorate ion is <u>perchloric acid (HClO₄)</u>.
(b) NO₃⁻ ion:
The acid that furnish NO₃⁻ ions is <u>Nitric acid (HNO₃)</u>.
(c) bromite (BrO₂⁻) ion:
The acid that furnish BrO₂⁻ ions is <u>Bromous acid (HBrO₂)</u>.
(d) H₂PO₄⁻ ion:
The acid that furnish H₂PO₄⁻ ions is <u>Phosphoric Acid (H₃PO₄)</u>.
Yes they are a pure substance