Answer:
8 m
Explanation:
3.0 x 10*8 divided by 3.75 x 10*7 = 8 m
Answer: There are
molecules present in 183.2 grams of
gas.
Explanation:
Given: Mass = 183.2 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of water is 18 g/mol. Therefore, moles of
are calculated as follows.

According to the mole concept, there are
molecules present in one mole of a substance.
Hence, molecules present in 10.17 moles are calculated as follows.

Thus, we can conclude that there are
molecules present in 183.2 grams of
gas.
Answer:
The answer is 2i on right hand side.
Explanation:
We should star by checking the equation from right.
First we check how many Zn r there in left hand side. Which is 1. Let us check how many Znr there in right hand side, there is 1.So Zn is balanced, and don't worry about Znplus2 on right hand side it is just the ions not how many zinc r there.
Now let us check how many I are there left hand side. Which is 2. Now how many I are there in right hand side? Only 1.
So we put 2 behind I.
Now there r 2 I on both sides.
Its simple actually.
Answer:
the ion present in the original solution is Ca2+
Explanation:
Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.
<u>Step1</u> : If we add Nacl to the solution, there is no precipitate formed
⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present
<u>Step2</u> : If we add Na2SO4 to the solution, a white precipitate is formed
The possible ions to bind at SO42- are Ca2+ and Fe2+
But the white precipitate formed, points in the direction of Ca2+
⇒This means calcium is present
<u>Step3</u> : If we add Na2CO3 to the filtered solution, there is a precipate formed
Ca2+ will bind also with CO32- and form a precipitate
So the ion present in the original solution is Ca2+