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3 years ago

Balance the chemical equation. _Mg + _Fe2O^3 -> _MgO + _Fe

Chemistry

1 answer:

VMariaS [17]3 years ago

8 0

Answer:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

Explanation:

To balance the equation, you should apply the law of conservation of mass for the equations.

The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).

The balanced equation is:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

That 3.0 mole of Mg react with 1.0 mole of Fe₂O₃ to produce 3.0 moles of MgO and 2.0 moles of Fe.

The no. of all atoms is the same in both of reactants and products side.

Mg (3), Fe (2), and O (3).

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Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am

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Answer: The average atomic mass of copper is 63.55 amu.

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$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For $_{29}^{63}\textrm{Cu}$ isotope:

Mass of $_{29}^{63}\textrm{Cu}$ isotope = 62.94 amu

Percentage abundance of $_{29}^{63}\textrm{Cu}$ = 69.17 %

Fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope = 0.6917

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Mass of $_{29}^{65}\textrm{Cu}$ isotope = 64.93 amu

Percentage abundance of $_{29}^{65}\textrm{Cu}$ = 30.83 %

Fractional abundance of $_{29}^{65}\textrm{Cu}$ isotope = 0.3083

Putting values in equation 1, we get:

$\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu$

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3 years ago

Identify the element in period 3 to most likely have similar chemical properties to Ca.

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Answer: The element having similar chemical properties that of calcium present in period 3 is magnesium.

Explanation:

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

We are given:

Calcium is the 20th element of the periodic table having electronic configuration $1s^22s^22p^63s^23p^64s^2$

It has 2 valence electrons.

The element present in period 3 and have the same number of valence electron or in the same group is magnesium.

Hence, the element having similar chemical properties that of calcium present in period 3 is magnesium.

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4 years ago

Balance the chemical equation. ___Mg + ___Fe2O^3 -> ___MgO + ___Fe

Balance the chemical equation. _Mg + _Fe2O^3 -> _MgO + _Fe