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zheka24 [161]
3 years ago
15

A grasshopper jumps and accelerates at 4.5 m/s2. If its legs exert a force of 0.062 N during the jump, what is the mass of the g

rasshopper?
Physics
1 answer:
Naily [24]3 years ago
5 0

Answer:

0.014 kg

Explanation:

trust me its right i took the assessment and got 100%.  :)

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An object moves from the position +16m to the position +43m in 12s. What us the total displacement
NeX [460]

First method

initial distance = 16m

final distance= 43 m

total distance covered= final -initial

                                     =43m -16m

                                     =27m

Second method

Si= 16m

Sf =43 m

t= 12 s

first we will find V

V =  (Sf-Si)/ t

V =( 43- 16)/ 12

V = 27/12  ⇒ V= 9/4

V= distance / time

distance= V×time

distance = (9/4) ×12

distance =27

3 0
3 years ago
Brutus, a champion weight lifter, raises 220 kg a distance of 3.10 m. (a) how much work is done by brutus lifting the weights? j
Nana76 [90]
A) work = force * distance 
mass is not a force, weight is, so we have to find the weight of the block. 
Weight = mg 
Weight = (220kg)(9.8) 
Weight = 2156N 
Work = 2156N * 3.10m 
work = 6683.6J 
b) Since he is holding the weights, it's not moving, therefore, he doesn't do any work 
c) The answer is still the same amount of work when he lifted them. 
d) The answer is no since when he let go the weight, he doesn't apply any force to the weight. 
e) P = work/time 
P = 6683.6J / 2.1s 
P = 3182.67 watts 
3 0
3 years ago
How do you find a rate of deceleration
Irina18 [472]
To find the rate of deceleration, subtract the initial velocity from the final velocity.
4 0
3 years ago
Read 2 more answers
A bullet with a mass of 0.1 kg is travelling at
mel-nik [20]

The block with the bullet lodged in the block is now travelling at 2.133 m/s.

<h3>What is momentum conservation principle?</h3>

When there is no external force acting on the system, the momentum remains conserved.

For inelastic collision, after collision both objects travel with common speed.

m1u1 + m2u2 =(m1 +m2)v

Substitute initial velocity of bullet u1 =320 m/s , initial velocity of block u2 =0, mass of bullet m1 = 0.1 kg and mass of block m2 = 14.9 kg.

Solve for the final velocity of bullet,

0.1 x 320 + 14.9 x 0 = (0.1 +14.9) x v

v = 2.133 m/s

Thus, the  block with the bullet lodged in block now travelling at 2.133 m/s.

Learn more about momentum conservation principle.

brainly.com/question/14033058

#SPJ1

6 0
2 years ago
True or false. Distance is always at the top of the triangle.<br> True<br> False
vekshin1

Answer:

TRUE

Explanation:

5 0
3 years ago
Read 2 more answers
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