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suter [353]
4 years ago
14

A student boils water in a can and puts the hot can carefully in very icy water. The can immediately crushes due to the change i

n pressure caused by the rapid temperature change. This is an example
Combined Gas Law

Gay-Lussac's Law

Charles' Law

Boyle's Law
Physics
1 answer:
hammer [34]4 years ago
8 0

Answer:

By elimination I know it's not CGL and I know it's not Charle's Law.

Gay-Lussac's law states the pressure of a a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. I think it's Gay-Lussac's Law.

Boyle's law states that pressure of a gas tends to increase as the volume of the container decreases which I got from a google search because I didn't know what it was.

CGL is the combined formula of all of these laws by the way

Charle's law is just gas expands when heated.

Gay-Lussac's is the best answer choice in my opinion

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A race car moves along a circular track at a speed of 0.512 m/s. If the car's centripetal acceleration is 15.4 m/s2, what is the
tiny-mole [99]

Answer:

The radius is  r = 0.0170 \ m  

Explanation:

From the question we are told that

      The speed at which the race car moves is v  =  0.512 \ m/s

       The centripetal acceleration is  a _r  =  15.4 \ m/s

Generally the centripetal acceleration is mathematically represented as

           a_r =  \frac{v^2 }{r}

=>        15.4  =  \frac{0.512^2 }{ r}

=>       r = 0.0170 \ m  

 

6 0
3 years ago
A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ
Neporo4naja [7]
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
F=ma
Using m=65 kg and a=5 m/s^2, we can find the value of the force applied to the roller-blade to obtain this acceleration:
F=(65 kg)(5 m/s^2)=325 N
3 0
3 years ago
During a breath, the average human lung expands by about 0.50 l. part a if this expansion occurs against an external pressure of
saveliy_v [14]
Work, in thermodynamics, is the amount of energy that is transferred from one system to another system without transfer of entropy. It is equal to the external pressure multiplied by the change in volume of the system. It is expressed as follows:<span>

W = PdV

Integrating and assuming that P is not affected by changes in V or it is constant, then we will have:

W = P (V2 - V1)

Substituting the given values:
P = 1.0 atm = 101325 Pa
(V2 - V1) = 0.50 L = 
W = 101325 N/m^3 ( 0.50) (1/1000) m^3
W = 50.66 N-m or 50.66 J
<span>
So, in the expansion process about 50.66 J of work is being done.
</span></span><span><span>
</span></span>
8 0
3 years ago
A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and
iogann1982 [59]

Answer:

p_2 = 1.76 atm

Explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}

Putting the values

\frac{1.15*2.37}{280}  =\frac{p_2 *1.68}{304}

9.733*10^{-3} = \frac{p_2 *1.68}{304}

9.733*10^{-3}*304 = p_2*1.68

\frac{9.733*10^{-3}*304}{1.68} =p_2

p_2= 1.76 atm

7 0
4 years ago
Why is water important in cells?
Makovka662 [10]
Because without water they wouldn't able to remove waste, bring in nutrients or move oxygen around. BTW there is a bout 65% of water in the adult human body.
4 0
3 years ago
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