If an initial cardioversion attempt is unsuccessful in a 33-pound child, you should repeat the procedure using 30 joules.
Cardioversion
Cardioversion is a medical therapy that uses medications or electricity to restore a normal heart rhythm to someone who has an abnormally high heart rate (tachycardia) or another cardiac arrhythmia. Synchronized electrical cardioversion restores the activity of the heart's electrical conduction system by applying a therapeutic dosage of electric current to the heart at a specified point in the cardiac cycle. (Defibrillation is the most efficient form of resuscitation for cardiac arrest caused by ventricular fibrillation and pulseless ventricular tachycardia. It delivers a therapeutic dosage of electric current to the heart at an unpredictable point in the cardiac cycle. Chemical cardioversion, also known as pharmacologic cardioversion, substitutes antiarrhythmic drugs for an electrical shock.
To learn more about cardioversion refer here:
brainly.com/question/11601470
#SPJ4
Use formula 1/2(m)(v square)
1/2(2000)(24 square)= 576000J
Answer:
Time period at the moon will be 2.828 sec
Explanation:
Let initially the length of the pendulum is l and acceleration due to gravity is g
And time period is given T = 2 sec
So time period of the pendulum is equal to
-------------eqn 1
Now on the planet acceleration due to gravity ![g_{new}=\frac{g}{2}](https://tex.z-dn.net/?f=g_%7Bnew%7D%3D%5Cfrac%7Bg%7D%7B2%7D)
So time period of the pendulum at this planet
--------eqn 2
Now dividing eqn 1 by eqn 2
![\frac{T}{T_{new}}=\sqrt{\frac{\frac{g}{2}}{g}}](https://tex.z-dn.net/?f=%5Cfrac%7BT%7D%7BT_%7Bnew%7D%7D%3D%5Csqrt%7B%5Cfrac%7B%5Cfrac%7Bg%7D%7B2%7D%7D%7Bg%7D%7D)
![T_{new}=\sqrt{2}T=1.414\times 2=2.828sec](https://tex.z-dn.net/?f=T_%7Bnew%7D%3D%5Csqrt%7B2%7DT%3D1.414%5Ctimes%202%3D2.828sec)
So time period at the moon will be 2.828 sec
Answer:
Explanation:
In Coulomb's law the force between the charged objects depends on the distance between them which is inversely proportional to the force and the charge of the objects which is directly proportional to the force with proportional constant K.
Because q₂ is near to another charged object q₁, then, it will experience an electric force exerted by q₁.
F₁₂ = K |q₁| |q₂|/r²
= K (|-e|) (|+e|)/r²
= (9.0 x 10⁹ N.m²/C²) x (1.6 x 10⁻¹⁹ C) x (1.6 x 10⁻¹⁹ C)/ (0.80 x 10⁻⁹)²
= 3.6 x 10⁻¹⁰ N
Force F₁₂ = F₂₁
Because the two charged objects have different signs , then, the force between them will be an attractive force.