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3 years ago

5) Find the initial velocity for a 700 kg car that

Physics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

Other angles of Net force would result in various initial velocities.

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The difference between a molecule and a compound is that a compound is made up of atoms from

defon

Answer:

The difference between a molecule and a compound is that a compound is made up of atoms from different elements.

3 0

3 years ago

A bicycle and a tennis ball are both at the top of a hill storing potential energy. If they both start rolling down the hill at

DochEvi [55]

Answer:

a bicycle has more kinetic energy cuz kinetic energy depends on mass and velocity.bicycle has more mass than a tennis ball.

3 0

3 years ago

The friction between a nonmoving object and the surface is resting on is called..?

Tamiku [17]

Answer:

Static friction exists between a stationary object and the surface on which it is resting. It prevents an object from moving against the surface. Example: Static friction prevents an object like a book from falling of the desk, even if the desk is slightly tilted

Explanation:

hope this helped

7 0

3 years ago

Build a second circuit with a battery and a light bulb but this time add a switch. Your circuit might look something like the on

kompoz [17]

Answer:

the resistance of the wire has no effect on the brightness of the bulb.

Explanation:

Let's apply ohm's law for your light bulb circuit plus wires plus switch

V = I R_{bulb} + I R_ {wire}

the current in a series circuit is constant

V = I (R_{bulb} + R_{wire})

To know the effect of the wires on the brightness of the bulb, we must look for the value of the typical resistance of these elements.

Incandescent bulb

Power 60 W

let's use the power ratio

P = V I = V2 / R

R = V2 / P

the voltage value for this power is V = 120 V

R = 120 2/60

R_bulb = 240 Ω

Resistance of a 14 gauge copper wire (most used), we look for it on the internet

R = 8.45 Ω/ km

in a laboratory circuit approximately 2 m is used, so the resistance of our cable is

R = 8.45 10⁻³ 2

R_wire = 0.0169 Ω

let's buy the two resistors

R_{bulb} = 240

R_{wire} = 0.0169

$\frac{R_{bulb} }{R_{wire} } = \frac{240 }{ 0.0169}$

$\frac{ R_{bulb} }{ R_{wire} } = 1.4 \ 10^4$

therefore resistance of the bulb is much greater than that of the wire, therefore almost all the power is dissipated in the bulb.

In summary, the resistance of the wire has no effect on the brightness of the bulb.

6 0

3 years ago

SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME

puteri [66]

Answer:

so true though

Explanation:

8 0

3 years ago