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3 years ago

What is the greatest common factor for 20y^9+5y^6

Mathematics

1 answer:

kompoz [17]3 years ago

3 0

Answer:

Your answer would be 5y=6

Hope this helps!

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What is the answer to 17=5k-2

nadezda [96]

17=5k-2

[add 2 on both sides]

19=5k

[divide 5 on both sides]

k=19/5(3.8)

HOPE THIS HELPS!!!!!!

6 0

3 years ago

Read 2 more answers

Find the x and y intercepts for the following equation. 2x– 7y=-14

Kisachek [45]

Answer:

C: Xint = 2, Yint. = -7

Step-by-step explanation:

Given the equation, 2x - 7y = -14:

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates (0, b). It is also the value of y when x = 0. To solve for the y-intercept, set x = 0:

2x - 7y = -14

2(0) - 7y = -14

0 - 7y = -14

-7y = -14

Divide both sides by -7 to solve for y:

-7y/-7 = -14/-7

y = 2

Therefore, the y-intercept = 2.

Next, the x-intercept is the point on the graph where it crosses the x-axis, and has coordinates, (a, 0). To find the x-intercept, set y = 0 and substitute into the given equation:

2x - 7y = -14

2x - 7(0) = -14

2x - 0 = -14

2x = -14

Divide both sides by 2 to solve for x:

2x/2 = -14/2

x = -7

x-intercept = -7.

Therefore, the correct answer is C: Xint = 2, Yint. = -7

Please mark my answers as the Brainliest if you find this helpful :)

7 0

2 years ago

FIRST PERSON WHO ANSWERS THIS WILL BE BRAINLIEST

djverab [1.8K]

Answer:

2.- 100

Step-by-step explanation 1:

$\frac{7}{25} + \frac{3}{4} = \frac{28}{100} + \frac{75}{100} = \frac{103}{100}$

↑ As we can see, the only common multiple between 4 and 25 that is given to is 100.

Step-by-step explanation 2:

$\frac{(7 * 4) + (3 * 25)}{4 * 25} = \frac{28 * 75}{100} = \frac{103}{100}$

↑ Another way of knowing the answer is by using a fraction solving method. As we can see, the denominator is once again 100.

Hope it helped,

BiologiaMagister

3 0

3 years ago

Which of the following points are solutions to the system of inequalities shown below?

pychu [463]

This is easy, love. It's E

3 0

3 years ago

Read 2 more answers

If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta

Ivahew [28]

Step-by-step explanation:

We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

$\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}$

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

PQ = Opposite side
QR = Adjacent side
RP = Hypotenuse
∠Q = 90°
∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

$\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}$

Since, we know that,

cosθ = 5/13
QR (Adjacent side) = 5
RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

$\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}$

$\rule{200}{3}$

$\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

$\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}$

Where,

Opposite side = 12
Hypotenuse = 13

Therefore,

$\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}$

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

$\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}$

By substituting the values, we get,

$\rule{200}{3}$

$\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the required answer is 17/7.

6 0

2 years ago