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3 years ago

11. Write the balanced equation for the reaction of HC2H3O2 with Al(OH)3 to form H2O and AI(C2H3O2)3

Chemistry

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

3HC2H3O2(aq) + Al(OH)3(aq) --> AI(C2H3O2)3(aq) + 3H2O(l)

Explanation:

HC2H3O2 is the chemical formula for Ethanoic acid which can be written as CH3COOH.

Hence, the balanced equation is stated as 3CH3COOH(aq) + Al(OH)3(aq) --> AI(CH3COO)3(aq) + 3H2O(l)

Acid + base → Salt + Water.

The equation is a neutralization reaction in which the acid, aqeous CH3COOH reacts completely with an appropriate amount of base, aqueous Al(OH)3 to produce salt, aqueous AI(CH3COO)3(aq)

and water, liquid H2O only.

During this reaction, the hydrogen ion, H+, from the Ethanoic acid is neutralized by the hydroxide ion, OH-, from the Aluminum hydroxide to form the water molecule, H2O and aluminium ethanoate.

Thus, it is called a neutralization reaction.

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Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a

Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

$P_1T_2=P_2T_1$

Where, $T_1$ and $T_2$ are initial and final temperatures, $P_1$ and $P_2$ are initial and final pressures.

$T_1$ = 20.3 + 273.15 = 293.45 K

$T_2$ = -2.0 + 273.15 = 271.15 K

$P_1$ = 1.02 atm

$T_2$ = ?

Let's plug in the values in the equation and solve it for final pressure.

$1.02atm(271.15K)=P_2(293.45K)$

$P_2=\frac{1.02atm*271.15K}{293.45K}$

$P_2$ = 0.942 atm

So, the new pressure of the jar is 0.942 atm.

5 0

4 years ago

What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP

Drupady [299]

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

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3 years ago

If you can answer as many of these as possible that would be great, will give thanks, 5 stars, and brainliest :)

alexandr1967 [171]

Answer:

The nucleus of the atom as suggested by "nuclear" chemistry.
Radioactive element are generally very large due to both their high number of protons, neutrons, and electrons.
An excessive amount of protons or neutrons.
Periodic table, table O, and table N.
Personal opinion question.
The atomic number.
It represents the number of protons, and can also represent the number of electrons in a neutral atom (an atom with no charge).
Protons ---- element.
Random, self-generated.
Gamma radiation is the only thing on table O that is mass less. Close to being the same is Beta particles which have almost no mass.
Neutrons and Gamma radiation.
Gamma radiation.
Electrons and Beta particles.
To turn one element into the isotope of another. Yes, I believe it is aptly named because you are changing the identity of the element.
The number of protons because they are what define the identity of an element.

Goodluck!

3 0

3 years ago

A 2g sample of crystals dissolve very slowly in 100mL of water while the water is stirred. Which of these would cause the crysta

liraira [26]

The stirring breaks it up faster, the amount of water doesn’t effect it, it just gives it space to spread/dissolve - I think.

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3 years ago