1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Delvig [45]
2 years ago
7

28. Element X is powerful enough to reduce sodium ions to sodium metal. Barium is a strong enough reducing agent to reduce X +to

X. What is the identity of element X? _____________
Chemistry
1 answer:
pantera1 [17]2 years ago
6 0

Answer:

hope it's correct.

Explanation:

element is nickel.

You might be interested in
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation:
Leni [432]

Answer: (1)CaSO4 -> (2)O2 + (1)CaS

Explanation: edge 2020 chem

5 0
2 years ago
What is the identity of an ion having 46 protons, 42 electrons and 60 neutrons?
Anon25 [30]

Answer:

first u lick it then out some sliva on it then rub it and once the volcano erupts u put it back in ur mouth and blow real hard ok!

Explanation:

repeat this process till the dong bleeds!

3 0
2 years ago
The _________________ are either elements or compounds which are present prior to a chemical reaction.
mr Goodwill [35]
Reactants would be the missing word in the sentence because they make up the products in a chemical reaction
3 0
2 years ago
Read 2 more answers
Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.
Ad libitum [116K]

Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

7 0
3 years ago
(Science)<br> why is the 10g of shampoo is more dense than the 10kg of the same shampoo?
igor_vitrenko [27]
Grams (g) is much lighter than kilograms (kg)
6 0
3 years ago
Other questions:
  • For which purpose do biochemists insert human genes into bacteria?
    7·2 answers
  • Can a tank of oxygen gas ever be half empty? explain
    11·2 answers
  • The phase of matter can be changed by:
    14·2 answers
  • _________ refers to the total energy of a system.
    5·2 answers
  • What is physical and chemical change ?
    7·1 answer
  • Help on science please!
    14·1 answer
  • What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin
    9·1 answer
  • How many grams of H2 will be produced, given 27.4 g of Al to start with?
    6·1 answer
  • Please please please please help
    5·1 answer
  • The reactants A and B react completely in a sealed container to form a product. What is the mass of the product of the reaction
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!