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3 years ago

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28. Element X is powerful enough to reduce sodium ions to sodium metal. Barium is a strong enough reducing agent to reduce X +to

X. What is the identity of element X? _____________

1 answer:

pantera1 [17]3 years ago

6 0

Answer:

hope it's correct.

Explanation:

element is nickel.

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A prairie dog runs into its burrow as a coyote approaches.This behavior helps the prairie dog

Nookie1986 [14]

This behavior helps the prairie dog from being prey upon by coyote.
Prairie dogs live in burrow and they normally do not move much away from their burrows. When they sense danger they will dash quickly back into their burrows. This behavioral adaptation protect them from predators.

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4 years ago

How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mas

Mandarinka [93]

<span>We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m. m * 0.875 = 275 g * 0.55 --> m = 173 g What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.

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3 years ago

A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]

Mnenie [13.5K]

<u>Answer:</u> The hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

<u>Explanation:</u>

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M$

The chemical reaction for aniline and HCl follows the equation:

$C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-$

<u>Initial:</u> 0.24 0.060 0.31

<u>Final:</u> 0.18 - 0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})$

$pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of benzoic acid = 4.2

$[C_6H_5COO^-]=0.18M$

$[C_6H_5COOH]=0.37M$

pH = ?

Putting values in equation 1, we get:

$pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89$

To calculate the hydronium ion concentration in the solution, we use the equation:

$pH=-\log[H_3O^+]$

pH = 3.89

Putting values in above equation, we get:

$3.89=-\log[H_3O^+]$

$[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M$

Hence, the hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

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3 years ago

A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.

erastovalidia [21]

The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)

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3 years ago

The pressure exerted by a gas on its container is inversely related to its Kelvin temperature

Lelu [443]

False, as pressure increases, temperature increases, given that other factors stay the same.

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3 years ago