Below is mgo. draw the structure of co2 and use curved arrows to show the movement of electron pairs. include lone electron pair

Question

Dominik [7]

2 years ago

12

Below is mgo. draw the structure of co2 and use curved arrows to show the movement of electron pairs. include lone electron pair

s.

Chemistry

2 answers:

son4ous [18] · Answer 1 · 2022-09-04T17:55:10+03:00

The movement of electron pairs is shown in the attached image.

Further explanation:

<u>Chemical bond:</u>

The attraction between atoms, molecules or ions that is responsible for the formation of chemical compounds is known as a chemical bond. It is formed either due to electrostatic forces or by the sharing of electrons. There are many strong bonds such as ionic bonds, covalent bonds, and metallic bonds while some weak bonds like dipole-dipole interactions, London dispersion forces, and hydrogen bonding also exist.

Ionic compound:

As the name suggests, these compounds have ions as their constituent particles. Out of two bonded atoms, one forms cation by the loss of electrons while other becomes anion by the gain of electrons.

Covalent compound:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds or molecular compounds are those compounds which are formed by the electron sharing between two or more non-metals.

The given reaction is as follows:

${\text{MgO}} + {\text{C}}{{\text{O}}_{\text{2}}} \to {\text{MgC}}{{\text{O}}_{\text{3}}}$

Here, MgO reacts with ${\text{C}}{{\text{O}}_{\text{2}}}$ to form ${\text{MgC}}{{\text{O}}_{\text{3}}}$ . MgO is an ionic compound whereas ${\text{C}}{{\text{O}}_{\text{2}}}$ is a covalent compound.

Oxygen is more electronegative than magnesium so the electrons are attracted to it. Oxygen develops negative charge and becomes ${{\text{O}}^{2 - }}$ while magnesium acquires positive charge and becomes ${\text{M}}{{\text{g}}^{2 + }}$ . The negative charge on oxygen thus reacts to the carbon of ${\text{C}}{{\text{O}}_{\text{2}}}$ , resulting in the formation of ${\text{CO}}_3^{2 - }$ . The movement of electron pairs is shown in the attached image.