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Gekata [30.6K]
4 years ago
13

Based on your data, what is the likely identity (complete chemical formula) of the unknown sulfate? Explain (include calculation

s as appropriate).
Mass (g) of unknown sulfate = 0.53g

mass g of crucible= 28.63g

mass g of crucible + content= 29.44 g

mass of barium sulfate = .81g
Chemistry
1 answer:
mash [69]4 years ago
6 0

Answer:

IDK

Explanation:

IDK

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A car designer is designing a new model of a popular car. He wants to use the same engine as in the old model but improve the ne
DaniilM [7]

The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. F = ma; a = F/m. This means that Force over the mass. In order to improve the acceleration without redesigning is that the company has to improve the force assuming that the mass is still the same.



4 0
3 years ago
How many hours are in 1987 seconds. Please explain
blagie [28]

Just divide!

60 seconds = 1 min

60 mins = 1 hour

1987 seconds divided by 60 seconds = 33.11 minutes

Your answer would be 33 minutes and 11 seconds

8 0
3 years ago
a calorimeter contained 75.0 g of water at 16.95 C. A 93.3-g sample of iron at 65.58 C was placed in it, giving a final temperat
Nostrana [21]

Answer:- \frac{382.69J}{0C} .

Solution:- Mass of Iron added to water is 93.3 g. Initial temperature of iron metal is 65.58 degree C and final temperature of the system is 19.68 degree C.

temperature change, \Delta T for iron metal = 65.58 - 19.68 = 45.9 degree C

specific heat for the metal is given as 0.444 J per g per degree C.

let's calculate the heat lost by iron metal using the equation:

q=mc\Delta T

where, q is the heat energy, m is mass, c is specific heat and delta T is change in temperature. let's plug in the values and calculate q for iron metal:

q=93.3g(45.9^0C)(\frac{0.444J}{g.^0C})

q = 1901.42 J

Using same equation we will calculate the heat gained by water.

mass of water is 75.0 g.

\Delta T for water = 19.68 - 16.95 = 2.73 degree C

specific heat for water is 4.184 J pr g per degree C. Let's plug in the values:

q=75.0g(\frac{4.184J}{g.^0C})(2.73^0C)

q = 856.674 J

Total heat lost by iron metal is the sum of heat gained by water and calorimeter.

So, heat gained by calorimeter = heat lost by iron metal - geat gained by water

heat gained by calorimeter = 1901.42 J - 856.674 J = 1044.746 J

Change in temperature for calrimeter is same as for water that is 2.73 degree C

For calorimeter, q=C.\Delta T

C=\frac{q}{\Delta T}

C=\frac{1044.746J}{2.73^0C}

C=\frac{382.69J}{0C}

So, the heat capacity of calorimeter is \frac{382.69J}{0C} .


4 0
3 years ago
Determine whether each of the molecules below is polar or nonpolar. Tetrahedral C C l 4 CClX4 Nonpolar Tetrahedral C H 3 O H CHX
liraira [26]

Answer:

CCl4 - Nonpolar

CH3OH - polar

NH3 - polar

CS2 - Nonpolar

Explanation:

One important thing that we should know is that polarity has to do with the presence of a resultant dipole moment in a molecule.

Dipole moment is a vector quantity, This means that its direction is also taken into account when discussing the dipole moment of molecules.

Hence, symmetrical molecules such as CS2 and CCl4 are non-polar even though they have polar bonds because their dipoles cancel out(zero resultant dipole moment).

On the other hand, NH3 and CH3OH are non-symmetrical molecules hence they possess an overall dipole moment and are polar molecules.

3 0
3 years ago
It takes Serina 0.25 hours to drive to school. Her route is 16 meters long. What is
Yakvenalex [24]

Answer:

60 (1 hour) × 0.25 = 15 minutes

15 ÷ 16 = 0.9375 meters per minute

5 0
4 years ago
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