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SVEN [57.7K]
3 years ago
12

You need to make 500 mL of a 3.40 M solution of sodium chloride. The only available solution is 1.5 M. Determine how to make the

needed dilution.
Chemistry
1 answer:
vlabodo [156]3 years ago
3 0

Answer:  (1.5 M) V1 = (3.40 M) (500mL)

            (multiply 3.40M x 500mL)    V1 = 1700 mL

1700 mL of the 1.5 M NaCl + 1200mL of water.

Explanation:

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if i got it right i think it woud be a

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3 years ago
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dexar [7]

Energy is stored in chemical bonds during photosynthesis.

During photosynthesis, the radiant energy from the sun is converted to chemical energy in carbohydrates.

Inorganic materials in the form of carbon dioxide and oxygen combine to form carbohydrates in the presence of radiant energy according to the equation below:

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The energy is thus, stored in chemical bonds in the carbohydrate and this is what is oxidized during respiration to release the locked energy.

More on photosynthesis can be found here: brainly.com/question/1388366

7 0
3 years ago
Read 2 more answers
When 3.51 g of phosphorus was burned in chlorine, the product was a phosphorus chloride. Its vapor took 1.77 times as long to ef
kumpel [21]

Answer:

<em>molar mass of the phosphorus chloride = 138.06 g/mol</em>

<em></em>

Explanation:

<em>mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.</em>

mass = 3.51 g

<em>lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec</em>

From this we can say that

rate of effusion of CO2 = 3.51/1 = 3.51 g/s

rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s

<em>From graham's equation of effusion</em>,

\frac{Rc}{Rp} = \sqrt{\frac{Mp\\}{Mc} }

Rc = rate of effusion of CO2 = 3.51 g/s

Rp = rate of effusion of phosphorus chloride = 1.98 g/s

Mc = molar mass of CO2 = 44.01 g/mol

Mp = molar mass of the phosphorus chloride = ?

Imputing values into the equation, we have

\frac{3.51}{1.98} = \sqrt{\frac{Mp\\}{44.01} }

1.77 = \frac{\sqrt{Mp} }{6.64}

11.75 = \sqrt{Mp}

Mp = 11.75^{2}

Mp = <em>molar mass of the phosphorus chloride = 138.06 g/mol</em>

5 0
3 years ago
Identifying Characteristics of the Gas Laws
elixir [45]

Answer:  The image from the question has the correct answers.

Explanation:  

As summarized in the attached table.

8 0
3 years ago
Determine if the bond between each pair of atoms is pure covalent, polar covalent, or ionic. drag the appropriate items to their
dsp73

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Pure Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For Br and Br,

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00         (Non Polar/Pure Covalent)

 

For N and O,

                    E.N of Oxygen      =   3.44

                    E.N of Nitrogen     =   3.04

                                                   ________

                    E.N Difference             0.40           (Non Polar/Pure Covalent)

 

For P and H,

                    E.N of Hydrogen       =   2.20

                    E.N of Phosphorous  =   2.19

                                                              ________

                    E.N Difference                  0.01          (Non Polar/Pure Covalent)

 

For K and O,

                    E.N of Oxygen          =   3.44

                    E.N of Potassium      =   0.82

                                                   ________

                    E.N Difference                2.62              (Ionic)

6 0
4 years ago
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