The height of the triangular base of the pyramid is calculated through the equation,
h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of x is 30°. Substituting,
h = (cos 30°)(18 in)
h = 15.59 in
Thus, the height of the base is approximately 15.59 inches.
Answer:
A
Step-by-step explanation:
V= BxHxL divided by 2
6x9x21= 1,134
divided by 2 equals 567yd
Answer:
9 and 11
Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.
n(n + 2) = 99
Solve for n.
n2 + 2n - 99 = 0
(n + 11)(n - 9) = 0 ⇒
Two solutions:
n = -11
n + 2 = -9
and
n = 9
n + 2 = 11
Test the answers.
The answer is C, 25% increase. To find the increase, subtract starting value (780) from the final value (975). It equals out to be 195. Divide 195 by the starting value which turns out to be 0.25. Then, multiply 0.25 by 100 which equals out to be 25.
Answer:
B (1 , 3) , D (1 , -2)
Step-by-step explanation:
∵ A (-3 , 3) , C (-3 , -2)
∵ They have the same x-coordinate
∴ AC is a vertical segment its length = 3 - -2 = 5
∵ The area of the rectangle = 20
∴ The width of it = 20 ÷ 5 = 4
∴ x-coordinate of B: -3 + 4 = 1
∴ y-coordinate of B : 3 ⇒ AB horizontal segment
∴ B (1 , 3)
∵ x-coordinate of BD is 1 ⇒ BD is vertical segment
∵ y-coordinate = 3 - 5 = -2
∴ D (1 , -2)
