A diodes are semiconductors offering a low resistance in one direction which allows current to flow through and opposes the movement of current in the other direction.

Diodes allow for only a unidirectional flow and conduction of electric current.

Unlike insulators, they can conduct electric current but in one direction.

Unlike conductors, they cannot conduct in both directions.

Most diodes are usually made of silicon and they find a wide range of application in modern electronics.

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3 0

3 years ago

A satellite orbits the Earth (mass = 5.98 x 1024 kg) once every = 43200 s. At what radius does the satellite orbit?

kap26 [50]

Answer:

26621 km

Explanation:

We are given;

Mass: m = 5.98 x 10^(24) kg

Period; T = 43200 s

Formula for The velocity(v) of the satellite is:

v = 2πR/T

Where R is the radius

Formula for centripetal acceleration is;

a_c = v²/R

Thus; a_c = (2πR/T)²/R = 4π²R/T²

Formula for gravitational acceleration is:

a_g = Gm/R²

Where G is gravitational constant = 6.674 × 10^(-11) m³/kg.s²

Now the centripetal acceleration of the satellite is caused by its gravitational acceleration. Thus;

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Plugging in the relevant values;

R = ∛((6.674 × 10^(-11) × 5.98 x 10^(24) × 43200²)/(4 × π²))

R = 26.621 × 10^(6) m

Converting to km, we have;

R = 26621 km

7 0

3 years ago

Ca+ is an example of a(n)

umka21 [38]

Answer:

Calcium

hope this helped mah dude :>

3 0

3 years ago

A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet fr

harina [27]

Answer:

$\frac{25}{3}ft/s$

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

$\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{15}{6}=\frac{x+y}{y}$

$\frac{5}{2}=\frac{x+y}{y}$

$5y=2x+2y$

$5y-2y=2x$

$3y=2x$

Differentiate w.r.t t

$2\frac{dx}{dt}=3\frac{dy}{dt}$

We have $\frac{dx}{dt}=5ft/s$

Substitute the value then we get

$2\times 5=3\frac{dy}{dt}$

$\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s$

Rate at which the tip of shadow is moving= $\frac{dx}{dt}+\frac{dy}{dt}$

Rate at which the tip of shadow is moving= $5+\frac{10}{3}=\frac{15+10}{3}ft/s$

Rate at which the tip of shadow is moving= $\frac{25}{3}ft/s$

5 0

3 years ago