Answer:
The distance from the building is 11.41 m.
Explanation:
Given that,
Speed = 30.0 m/s
Angle = 45.0°
Distance = 10.0 m
We need to calculate the vertical component
Using formula of vertical component
We need to calculate the time
Using equation of motion
Put the value into the formula
On neglecting of higher value of t
Then use the horizontal component
We need to calculate the distance
Put the value into the formula
Hence, The distance from the building is 11.41 m.
I will post my work, but is that 99 degrees Celsius and 25 degrees Celsius?
All you have to do is plug in the initial temperature for gold where it says Tg and the initial temperature for the water where it says Tw and then plug that in and you will have your answer.
Answer:
300m
Explanation:
step one
given data
initial speed u= 15m/s
final speed v= 45m/s
time taken to attain final speed= 10seconds
Step two:
Let us first solve for the acceleration
a= Δv/t
a= 45-15/10
a=30/10
a= 3m/s
applying the equation of motion
substituting our given data
collect like terms
2025-225=6s
1800=6s
divide both sides by 6
s=1800/6
s=300m
One possible consequence is that the warmer temperature cause the polar ice to melt even faster
Answer:
Explanation:
ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface
n₁sinθ₁ = n₂sinθ₂
1 sin52 = 1.33sinθ₂
θ₂ = arcsin(sin52 / 1.33)
θ₂ = 36°
as measured from the perpendicular to the surface