Which sequence shows the chain of energy transfers that create surface currents on the ocean?

Physics

1 answer:

Papessa [141]2 years ago

6 0

Answer:

The correct answer is A. The sun is the energy source of the surface currents in the ocean

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A blimp, suspended in the air at a height of 600 feet, lies directly over a line from a sports stadium to a planetarium. If th

MAXImum [283]

Answer:

1946 ft

Explanation:

The distance is the addition of the distance gotten from both triangles.

d = x + y

d = 1178 ft + 768 ft

d = 1946 ft

Attached is a picture showing how I arrived at the answer

3 0

3 years ago

What is the magnitude of δv12 if the bulb is removed from the socket (i.e. the circuit is not closed)?

andreev551 [17]

Since the circuit is incomplete or not closed, no current flows in the circuit. as per ohm's law , Voltage is directly proportional to current and is given as

V = Voltage = i R where i = current , R = resistance

as no current flows in the circuit, i = 0

the resistance R can not be zero. hence

V = 0 (R)

V = 0 Volts

so the magnitude of the Voltage is zero Volts

4 0

3 years ago

Read 2 more answers

Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi

nadya68 [22]

Answer:

$E = 1.85*10^{12}\frac{N}{C}$

Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction, and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

$E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}$