How would I do this problem? In trapezoid PQRS, PQ is parallel to SR. Find the area of PQRS. Leave your answer is simplest radic
1 answer:
Suppose that the altitude drawn intersects the base of PQRS at point T
With triangle RTQ, we see that angle T is 90° and angle R is 30°. Since the angles in a triangle always sum to 180°, angle Q is 180° - 90° - 30° = 60°. Thus, triangle RTQ is a 30°-60°-90° right triangle.
The sides of a 30°-60°-90° triangle are in ratio 1:√3:2 (this is in the form (side opposite to 30° angle):(side opposite to 60° angle):(side opposite to 90° angle)). The hypotenuse, the side opposite opposite to the 90° angle, has a length of 24. The altitude of the triangle, the side opposite to the 30° angle, therefore has a length of 24/2 = 12; and the base of the triangle, the side opposite to the 60° angle, has a length of 12√3
Therefore, the area of PQRS is
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Answer:
Option (3)
Step-by-step explanation:
Properties for the vertical stretch or shrink of a function,
If a function is f(x) = k|x|
1). Function will be vertically stretched if k > 1
2). Function will have a vertical shrink if 0 < k < 1
To fit the given data graph of f(x) = |x| will vertically shrink without any translation along x or y-axis.
And the value of k will be, 0 < k < 1.
Therefore, g(x) = will be the transformed graph.
Therefore, Option (3) will be the correct option.