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Dvinal [7]
4 years ago
12

An object density of 1.30 g/ml and a volume of 5.00 ml what is it’s mass

Chemistry
1 answer:
Mama L [17]4 years ago
5 0
Density=mass/volume                                                                                                    mass=densityxvolume                                                                                                    mass=1,3x5.0 mass=6.5g
                                               
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3 years ago
Which properties result from minimal interactions between molecules in a gas?
7nadin3 [17]
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5 0
3 years ago
f 4.2 moles of copper metal react with 6.3 moles of silver nitrate, how many moles of silver metal can be formed, and how many m
alex41 [277]
<span>1. Balance the reaction
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag 
2. Find the limiting [divide moles of reactant by their balancing numbers]
Cu: 4.2/1 =4.2 
AgNO3: 6.3/2= 3.15 
AGNO3 is the limiting
How many moles of silver metal will be formed?
The ratio between the limiting reactant and silver is 2:2 or 1:1
therefore 6.3 moles of silver will be formed.

How many moles of excess reactant will be left?
Since each mole of copper is equal to 2 moles of AgNO3. divide 6.3 by 2 then minus it from coppers moles
6.3/2 = 3.15
4.2-3.15 = 1.05 moles of copper will be left
</span>
7 0
3 years ago
6. A student was conducting an experiment to find the volume of a spherical metal object. He placed it in the graduated cylinder
Sergio039 [100]
<h3>Answer:</h3>

                No, it wouldn't affect the volume.

<h3>Explanation:</h3>

                         Let us suppose the masses of metal object before and after shape change to be,

                              Mass before shape change  =  2.5 g

                                Mass after shape change  =  2.5 g

As the shape change has not affected on the mass so in both states it will remain 2.5 g.

Secondly, as density will remain same for both states because it is intensive property of a particular matter and is considered a characteristic property. Hence, it will also remain constant before and after shape change. Assume the density to be 2 g.mL⁻¹.

Therefore the volume calculated will be,

Before shape change:

                                   Volume-1  =  Density × Mass

                                   Volume-1  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-1  =  5 mL

After shape change:

                                   Volume-2  =  Density × Mass

                                   Volume-2  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-2  =  5 mL

<h3>Conclusion:</h3>

                  The volume is not affected by changing shape. Hence, after shape change the object will be having a volume of 5 mL.

8 0
3 years ago
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