Answer:

Explanation:
Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.
- m= 1.85 kg
- g= 9.8 m/s²
- h= 2.23 m
Substitute the values into the formula.

Multiply the first 2 numbers together.

Multiply again.

- 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
- Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

The textbook has <u>40.4299 Joules of potential energy.</u>
Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is

KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
Answer:
161.57 K
Explanation:
V1/T1 = v2/T2
(5.24 L)/(411 K) = (2.06 L)/T2
T2 = 161.57 K
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