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professor190 [17]
3 years ago
10

Which properties result from minimal interactions between molecules in a gas?

Chemistry
1 answer:
7nadin3 [17]3 years ago
5 0
The liquids so play tank i am just completing my sdgsgr

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A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.601 mol of a gaseous product. If the cyli
netineya [11]

Answer:

4.33 L

Explanation:

Assuming ideal behaviour and that all 0.300 moles of gas reacted, we can solve this problem using Avogadro's law, which states that at constant temperature and pressure:

  • V₁n₂ = V₂n₁

Where in this case:

  • V₁ = 2.16 L
  • n₂ = 0.601 mol
  • V₂ = ?
  • n₁ = 0.300 mol

We <u>input the given data</u>:

  • 2.16 L * 0.601 mol = V₂ * 0.300 mol

And <u>solve for V₂</u>:

  • V₂ = 4.33 L
3 0
2 years ago
How to write 310,763,136 in expanded form
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Answer:

Explanation:

"Three hundred ten million, seven hundred sixty-three thousand, one hundred thirty-six".

8 0
3 years ago
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Given 6.98 x 10 4 power grams of iron, calculate the moles of iron present
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Answer:

1249.88 mol.

Explanation:

∵ no. of moles of Fe = mass of Fe/atomic weight of Fe.

<em>∴ no. of moles of Fe </em>= (6.98 x 10⁴ g)/(55.845 g/mol) = <em>1249.88 mol.</em>

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3 years ago
An amide may be produced by reacting an acid chloride with
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Answer:

An amide may be produced by reacting an acid chloride with ammonia.

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3 years ago
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The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
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