Answer:
The value of b is 12.5. The length of YZ is 100 units.
Step-by-step explanation:
Given information: XY=6b, YZ=8b, XZ=175 and Y is between X and Z.
It means X,Y, Z are collinear points and point Y divides the line segment XZ is two ports.
Using segment addition property, we get
![XY+YZ=XZ](https://tex.z-dn.net/?f=XY%2BYZ%3DXZ)
Substitute XY=6b, YZ=8b, XZ=175 in the above equation.
![6b+8b=175](https://tex.z-dn.net/?f=6b%2B8b%3D175)
![14b=175](https://tex.z-dn.net/?f=14b%3D175)
Divide both sides by 14.
![b=\frac{175}{14}](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B175%7D%7B14%7D)
![b=12.5](https://tex.z-dn.net/?f=b%3D12.5)
The value of b is 12.5.
The length of YZ is
![YZ=8b=8\times 12.5=100](https://tex.z-dn.net/?f=YZ%3D8b%3D8%5Ctimes%2012.5%3D100)
Therefore the length of YZ is 100 units.