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igomit [66]
3 years ago
12

Three cars, car x, car y, and car z, begin accelerating from rest, at the same time. car x is more massive than car y, which is

more massive than car z. the net force exerted on each car is identical. after 10 seconds, which car has the most amount of momentum?
Physics
1 answer:
Leviafan [203]3 years ago
6 0
Ah hah !  We can do this the easy way, or we can do it the hard way.

Whereas, in honor of, and pursuant to my natural laziness, I'm going to
do it the easy way, and not even talk about the hard way.  Please fasten
your seat belt.  It may be a boompy ride.


There are a few different ways to calculate the CHANGE in
an object's momentum.  For this particular problem, it's
best to use this equation for "Change in momentum":

CHANGE in momentum = IMPULSE delivered to the object.

Do you remember how to calculate impulse ?

Impulse = (force exerted in the object) x (time the force lasts) 

-- In the question, it says that the same force is exerted on each car,
and they all get it for 10 seconds apiece.

-- Since the force is the same on each car, and the force lasts for
the same amount of time on each car, the IMPULSE delivered to
each car is the same !

-- So the CHANGE IN MOMENTUM is the same for each car.

-- They all started out from 'rest', so each one started with zero momentum.

-- The CHANGE IN MOMENTUM is the same for each car.

-- So at the end of 10 seconds, NO CAR has the 'most momentum'.
All three cars have the SAME momentum.


Do you see why I said that this is the 'easy way' to solve it ?

 
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Energy is required to produce a chemical change during:.
pentagon [3]

Answer:

Electrolysis.

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3 years ago
Suppose the B string on a guitar is 24" long and vibrates with a frequency of about 247 Hz. You place your finger on the 5th fre
Rudiy27

Answer:

b. E (about 329 Hz)

Explanation:

Given data:

Initial length of the string l1= 24 in

initial frequency f1= 247 Hz

changed length l2= 18 in

Then we have to find the changed frequency f2= ?

We already now that

frequency f ∝ 1/length of the string l

therefore,

\frac{f_1}{f_2} =\frac{l_1}{l_2}

⇒{f_2}=\frac{l_1}{l_2}\times{f_1}

⇒{f_2}=\frac{24}{18}\times{247}

⇒{f_2}=329.33 Hz

7 0
3 years ago
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
3 years ago
Security is a major concern now that computers play such a large part in healthcare. To address this concern, as well as others
Fed [463]
The correct answer is C. HIPAA

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6 0
4 years ago
Read 2 more answers
A weightlifter curls a 30 kg bar, raising it each time a distance of 0.50 m .How many times must he repeat this exercise to burn
ludmilkaskok [199]

Answer:

N = 2141 times

Explanation:

Each time the work done to raise a given mass is

W = mgh

here we know that

m = 30 kg

h = 0.50 m

now we have

W = (30 kg)(9.81 m/s^2)(0.50)

W = 147.15 J

since it is just 25% of actual energy consumed as we know its efficiency is 25%

so we have total energy consumed in this way

E_{total} = \frac{147.15}{0.25}

E_{total} = 588.6 J

now if it took N number of times so burn the fat of a pizza then

N(588.6) = 1260 \times 10^3

N = 2141 times

4 0
3 years ago
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