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blsea [12.9K]
3 years ago
15

The solids settled at the bottom is called a) sludge b) sewage c) waste d) litter

Physics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

the solid particles that settle down at the bottom of the container are known as sediment.

Explanation:

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Determine the energy, in electron volts, of an emitted photon when an electron transition from n=3 to n=2 occurs
tensa zangetsu [6.8K]
Give me some answer choices and i will be happy to help
7 0
4 years ago
What is the momentum of a 72 kg baseball player who slides into home plate
Alina [70]

Answer:

B) 350 kg m/s

Explanation:

momentum or p is given by the equation p= mxv

We have the mass and velocity so we can use the equation directly

p= 72kg x 4.9 m/s

p= 352.8 kg m/s

4 0
3 years ago
The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve
Katena32 [7]

Answer:

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

\varepsilon _t=\dfrac{D-d}{d}

\varepsilon _t=\dfrac{32-30}{30}

\varepsilon _t=0.0667

We know that

n=-\dfrac{\epsilon _t}{\varepsilon _{long}}

\varepsilon _{long}=-\dfrac{\epsilon _t}{n}

\varepsilon _{long}=-\dfrac{0.0667}{0.45}

\varepsilon _{long}=-0.148

So the axial pressure

P=E\times \varepsilon _{long}

P=5\times 0.148

P=740 KPa

The movement in the sleeve

\Delta =\varepsilon _{long}\times L

\Delta =0.148\times 50

Δ=7.4 mm

6 0
3 years ago
The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make i
balandron [24]

Answer:

The answer is

<h2>84.9 kPa</h2>

Explanation:

Using Boyle's law to find the final pressure

That's

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

P_2 =  \frac{115000 \times 480}{650}  = \frac{55200000}{650}  \\  = 84923.076923...

We have the final answer as

<h3>84.9 kPa</h3>

Hope this helps you

7 0
3 years ago
A 66.0−kg short-track ice skater is racing at a speed of 10.0 m/s when he falls down and slides across the ice into a padded wal
dexar [7]

Answer:

3300J

Explanation:

Work done is the energy that is lost by the skater

Formula for workdone = 1/2*mV^2

m = 66kg

V = 10m/s

Work done = 1/2 * 66 * 10^2

= 3300J

7 0
3 years ago
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