Question

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Answer 1

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Answer 2

For this case we must find the value of "x" of the following equations:

Equation 1:

$8 = 2x + 4$

We subtract 4 on both sides of the equation:

$8-4 = 2x\\4 = 2x$

We divide between 2 on both sides of the equation:

$\frac {4} {2} = \frac {2x} {2}\\x = 2$

Equation 2:

$64x = 16x-1$

We subtract 16x on both sides of the equation:

$64x-16x = -1\\48x = -1$

We divide between 48 on both sides of the equation:

$x = - \frac {1} {48}$

Answer:

Equation 1:$x = 2$

Equation 2: $x = - \frac {1} {48}$