Ashley ran with a speed of 12 feet per second.
Speed is measured as the ratio of the distance travelled to the time it took to cover that distance.
Since speed simply has a magnitude and no direction, it is a scalar quantity.
The formula for the speed of an object/body is given as-
where, d is the distance travelled by the body/object and t is the time taken by the body/object to cover the distance
Ashley has covered a distance of 264 feet and the time taken to cover this distance is 22 seconds.
Now, Ashley’s speed can be calculated by dividing the distance of 264 feet to the time taken by Ashley cover this distance, i.e.
Thus, the speed with which Ashley ran was 12 feet per second.
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Answer:
Magnetic force, F = 0.6 N
Explanation:
It is given that,
Length of the wire, L = 30 cm = 0.3 m
Current carrying in the wire, I = 0.5 A
Uniform magnetic field, B = 4 T
To find,
The magnetic force
Solve,
A force is exerted by the wire in the magnetic field that is given by :
Here,
F = 0.6 N
Therefore, the magnetic force exerted by the wire in the magnetic field is 0.6 N
Answer:
As a skydiver falls, he accelerates downwards, gaining speed with each second. The increase in speed is accompanied by an increase in air resistance so it depends
Explanation:
The displacement of end a is 1.09mm
given:
Rod diameter,d=20mm
stiffness constant,k=55mn/m
force,f=60kn
young modulus,E= 200gpa
we know the formula
By substituting values in the above formula
length L=A×E/K
=1.14m
Hence, displacement is
=1.09mm
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Answer:
9) a = 25 [m/s^2], t = 4 [s]
10) a = 0.0875 [m/s^2], t = 34.3 [s]
11) t = 32 [s]
Explanation:
To solve this problem we must use kinematics equations. In this way we have:
9)
a)
where:
Vf = final velocity = 0
Vi = initial velocity = 100 [m/s]
a = acceleration [m/s^2]
x = distance = 200 [m]
Note: the final speed is zero, as the car stops completely when it stops. The negative sign of the equation means that the car loses speed or slows down as it stops.
0 = (100)^2 - (2*a*200)
a = 25 [m/s^2]
b)
Now using the following equation:
0 = 100 - (25*t)
t = 4 [s]
10)
a)
To solve this problem we must use kinematics equations. In this way we have:
Note: The positive sign of the equation means that the car increases his speed.
5^2 = 2^2 + 2*a*(125 - 5)
25 - 4 = 2*a* (120)
a = 0.0875 [m/s^2]
b)
Now using the following equation:
5 = 2 + 0.0875*t
3 = 0.0875*t
t = 34.3 [s]
11)
To solve this problem we must use kinematics equations. In this way we have:
10^2 = 2^2 + 2*a*(200 - 10)
100 - 4 = 2*a* (190)
a = 0.25 [m/s^2]
Now using the following equation:
10 = 2 + 0.25*t
8 = 0.25*t
t = 32 [s]