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2 years ago

How much heat in joules is needed to raise the temperature of 10 grams of water from 25 c to 50 c?

Physics

1 answer:

natali 33 [55]2 years ago

4 0

Answer: 10.5 kJ

Explanation:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c = 4.18 J g ∘ C

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What happens to jetstream’s as they get closer to the equator

MAVERICK [17]

Answer:They stop because jet streams follow boundaries between hot and cold air.

Explanation:

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3 years ago

Read 2 more answers

A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.

kirill115 [55]

Answer:

Solution given:

height [H]=25m

initial velocity [u]=8.25m/s

g=9.8m/s

now;

a. How long is the ball in flight before striking the ground?

Time of flight =?

Now

Time of flight= $\sqrt{\frac{2H}{g}}$

substituting value

= $\sqrt{\frac{2*25}{9.8}}$
=2.26seconds

<h3>the ball is in flight before striking the ground for 2.26seconds.</h3>

b. How far from the building does the ball strike the ground?

Horizontal range=?

we have

Horizontal range=u* $\sqrt{\frac{2H}{g}}$

=8.25*2.26
=18.63m

<h3>The ball strikes 18.63m far from building. </h3>

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2 years ago

Which structure is found in all EUKARYOTIC cells? Large central vacuole, Golgi apparatus, flagella, cilia

Pavel [41]

The answer is Golgi apparatus.
HOPE THIS HELPS!

3 0

3 years ago

A spherical tank with radius 4 m is half full of a liquid that has a density of 900 kg/m3. The tank has a 1 m spout at the top.

kompoz [17]

The answer & explanation for this question is given in the attachment below.

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3 years ago

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 45.0 mph . Beth leaves Los A

WARRIOR [948]

Answer:

a.Beth

b.2232 s

Explanation:

We are given that

Distance,d=400 mi

Speed of Alan,v=45 mph

Speed of Beth,v'=55 mph

a.Time = $\frac{distance}{speed}$

Using the formula

Time taken by Alan= $\frac{400}{45}=8.89 hr$

Time taken by Beth= $\frac{400}{55}=7.27hr$

Alan will reach San Francisco at 4:53 PM

Beth will reach San Francisco at 4:16 PM

Beth will reach before Alan.

b.Difference between time=8.89-7.27=1.62 hr

t=1.62 hr

1.62-1=0.62 hr

0.62 hr= $0.62\times 60\times 60=2232 s$

Hence, Beth has to wait 2232 s for Alan to arrive .

6 0

3 years ago