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Setler79 [48]
3 years ago
5

Water molecules are listed from A to B to C in

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0
The answer is b, least to greatest motion.

The higher the temperature a substance is, their particles have more kinetic energy and thus move faster and have a faster motion.

From the pictures, we can see that the state changes from the coldest, ice, to the least cold, water, and to the hottest, steam. Therefore, the hotter the substance it, the water molecules have a greater motion.

So your answer is b.
Katarina [22]3 years ago
7 0

The answer is B, because my son just took the test and he got it right

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230 in scientific notation
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230 in scientific notation is:

2.3 x 10^2
7 0
4 years ago
What volume, in L, of a 6.3 M K2SO4 solution contains 44.1 g of K2SO4?
Alenkinab [10]
Answer:

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Comment if you need step to step explanation.
8 0
3 years ago
Why is a cis-1,3-disubstituted cyclohexane more stable thanits<br> trans isomer?
anzhelika [568]

Answer:

Explanation has been given below

Explanation:

  • In diaxial conformation of cis-1,3-disubstituted cyclohexane, 4 gauche-butane interactions along with syn-diaxial interaction are present. Hence it readily gets converted to diequitorial conformation where no such gauche-butane interaction is present
  • In two possible conformations of trans-1,3-disubstituted cyclohexane, 2 gauche-butane interactions are present in each of them.
  • Hence cis-1,3-disubstituted cyclohexane exists almost exclusively in diequitorial form. But trans-1,3-disubstituted cyclohexane has no such option.
  • Trans-1,3-disubstituted cyclohexane experiences gauche butane interaction in each of the two conformations.
  • Therefore cis-1,3-disubstituted cyclohexane is more stable than trans conformation

5 0
3 years ago
How many molecules of Mg3N2 (magnesium nitride) are formed when excess Mg (magnesium)
dybincka [34]

Explanation:

<em>3Mg(s) + N2(g) = Mg3N2(s)</em>

First check that the equation is balanced. In this case, it is.

Assuming that magnesium is the limiting reactant:

  1. First find the molecular weight using the Periodic Table.

       We find that the atomic mass of magnesium is approximately

       <em>24.3g</em>, so the molecular weight is just <em>24.3g\mol</em>

   

    2. Next we need the mole to mole ratio. As there are <em>3</em>

        magnesiums for <em>1</em> magnesium nitride (shown by the coefficients), the                    

        mole to mole ratio is<em> 1 mol Mg3N2\3 mol Mg.</em>

   

    3. We need the amount of the substance, in grams. Since you have not    

        stated it in the question, I'll just do <em>10g</em> AS AN EXAMPLE. Note that    

       depending on the amount, the LIMITING REAGENT MAY DIFFER.

   4.  Finally, we need the molecular weight of <em>Mg3N2</em>, which we can easily    

        calculate to be around <em>100.9\mol.</em>

<em />

   5.  Putting this all together, we have<em> 10gMg⋅ (mol Mg\24.3gMg) </em>

<em>         (1mol Mg3N2\ 3mol Mg) (100.9g Mg3N2\mol Mg3N2)</em>

     

        the units will cancel to leave <em>gMg3N2</em> (grams of magnesium nitride):

       

<em>        10gMg ⋅ (mol Mg\24.3gMg) (1mol Mg3N2\3mol Mg)</em>

<em>        (100.9g Mg3N2\mol Mg3N2)</em>

<em />

Doing the calculation yields approximately 13.84g.

Assuming that nitrogen is the limiting reactant:

Similarly, following the above steps but with <em>10g</em> of nitrogen yields <em>36.04g</em>

In conclusion, as we produce less amount of <em>Mg3N2</em> when we assumed that <em>Mg</em> was the limiting reagent, magnesium is the limiting reagent and nitrogen is the excess.

Note: This is in THIS CASE, where we have <em>10g</em> of both. The answer may vary depending on the amount of each substance.

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3 years ago
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