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Finger [1]
3 years ago
14

In a titration of 0.5 M HCl and an unknown concentration NaOH, 25.0 ml of NaOH was required to completely neutralize 25.0 ml of

HCl. What is the concentration of the NaOH?
Chemistry
1 answer:
baherus [9]3 years ago
6 0
When an acid is neutralized by a base, that means moles of H+ = moles of OH-

moles of H+ = 0.5 M * 0.025 L HCl = 0.0125 moles H+

moles of OH- should be equal to 0.0125 moles, so
0.0125 moles = (x) * 0.025 L NaOH

x is the concentration of NaOH, which we want to find.

x = 0.5 M

The correct answer is C) 0.5 M.
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Nina [5.8K]

Answer:2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

Explanation: A chemical change is a reaction in which chemical composition of the substance changes. Some bonds are broken and some new bonds are formed.

The reactants are written in terms of their chemical formula on the left hand side and the products are written in terms of their chemical formula on right hand side with a arrow in between. The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.

Thus the only reaction producing a gas is 2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

4 0
3 years ago
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One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2.
mart [117]

Answer:

  • <em>You could expect 3.48 grams of C₂H₄N₂</em>

Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

       8NH_3+5CO_2+3CH_4\rightarrow 4C_2H_4N_2 +10H_2O

3. Convert the mass of each reactant into number of moles:

<u>Formula:</u>

  • Number of moles = mass in grams/molar mass

<u>2.11g NH₃</u>

  • Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃

<u>14.9g CO₂</u>

  • Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂

<u>1.75g CH₄</u>

  • Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

         8molNH_3:5molCO_2:3molCH_4:4molC_2H_4N_2:10molH_2O

5. Limiting reagent

The available amounts of the reactants are:

  • 0.124 mol NH₃
  • 0.339 mol CO₂
  • 0.109 mol CH₄

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

  • 0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂

Since there are 0.339 moles available, this is in excess.

  • 0.124molNH₃ × (3molCH₄/8molNH₃) =  0.0465mol CO₂

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

  • 0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂

Convert to grams:

  • Mass = number of moles × molar mass
  • 0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer

4 0
3 years ago
Name the following compound: <br> HC2H3O2
just olya [345]

Answer:

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Explanation:

Cuando no se diluye, a veces se le llama ácido acético glacial . El vinagre es aproximadamente del 3 al 9% de ácido acético en volumen, lo que hace que el ácido acético sea el componente principal del vinagre, aparte del agua.

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Daniel [21]

The reactions are a bit poorly written. While it's true that aqueous H₂CO₃ is produced in this neutralization reaction, the H₂CO₃ rapidly decomposes to yield CO₂(g) and H₂O(l). Writing the product as H₂CO₃(aq) in the net ionic equation is unnecessarily confusing since it portrays the substance as nonionizing yet water-soluble.

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Answer: Imidogen

Explanation: I just looked it up.

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