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Pie
3 years ago
7

What is the mass in grams of 5.40 moles of lithium.

Chemistry
2 answers:
son4ous [18]3 years ago
6 0

<u>Answer:</u> The mass of lithium is 34.7 grams.

<u>Explanation:</u>

To calculate the mass of lithium for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Number of moles of lithium = 5.40 moles

Molar mass of lithium = 6.94 g/mol

Putting values in above equation, we get:

5.40mol=\frac{\text{Mass of lithium}}{6.94g/mol}\\\\\text{Mass of lithium}=(5.0mol\times 6.94g/mol)=34.7g

Hence, the mass of lithium is 34.7 grams.

Maslowich3 years ago
3 0
You would use the formula:

n = \frac{m}{M}

Where m is the mass, and M is molar mass (the periodic table would be used for this)

In this case, we need to rearrange the formula to find m

m = nM
    = 5.40 x 6.941
    = 37.5g

Hope this helped! Ask me if there's any part of the working you don't understand :)


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The dessert can be harsh environment with extreme heat during the day and cold during the night also there is very little rainfa
Sphinxa [80]

Answer:

True

Explanation:

The desert refers to a region of arid land which is characterized by extreme temperatures, extreme dryness, low amount of precipitation and generally harsh living conditions. Because of these harsh conditions, they have been tagged with various names ranging from 'Death Valley' to 'the place from where there is no return' etc.

Every desert is made up of 2 components:  the <u>biotic (living) component</u> and the <u>abiotic (non-living) component</u>. The biotic (living) component consists of the plants and animals that have adapted to these harsh living conditions e.g. Cactus or Cacti, Holly plants, Camels, Lizards, Snakes etc. The abiotic (non-living) component consists of climate (subtropical deserts which are extremely cold or temperate deserts which are extremely hot), location, precipitation/rainfall

8 0
3 years ago
How much concentrated solution would it take to prepare 2.75 L of 0.400 M HCl upon dilution with water
grin007 [14]
Hydrochloric acid is usually purchased in a concentrated form that is 37.0% HCl by mass and has a density of 1.20g/mL. Calculate the molarity of the concd HCl.
1.20 g/mL x 1000 mL x 0.37 x (1/36.5) = about 12 M or so but you do it exactly.

Then mL x M = mL x M
mL x 12 M = 2800 mL x 0.475
Solve for mL of the concd HCl solution.
7 0
2 years ago
How many liters of C3H6O are present in a sample weighing 25.6 grams?
Romashka [77]

Answer:

V = 0.0327 L.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:

V=25.6g*\frac{1mL}{0.784g}*\frac{1L}{1000mL}\\\\V=0.0327L

Regards!

7 0
3 years ago
Researchers used a combustion method to analyze a compound used as an antiknock additive in gasoline. A 9.394 mg sample of the c
LuckyWell [14K]

Answer:

The percent composition of the compound is 90.5 % C and 9.5 % H

Explanation:

Step 1: Data given

Mass of compound = 9.394 mg

Mass  of CO2 yielded = 31.154 mg

Mass of H2O yielded = 7.977 mg

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate moles CO2

moles of CO2 = (0.031154 g / 44.01 g/mol) = 7.08 * 10^-4 mol CO2

Step 3: Calculate moles C

moles of C = moles of CO2 * (1 mol C / 1 mol CO2)

moles of C = 7.08 * 10^-4 mol

Step 4: Calculate moles H2O

moles of H2O = (0.007977 g / 18.02 g/mol) = 4.43 * 10^-4 mol H2O

Step 5: Calculate moles of H

moles of H = moles of H2O * (2 mol H / 1 mol H2O)

moles of H =  4.43* 10^-4 *2 = 8.86 * 10^-4 mol H

Step 6: Calculate mass of C

mass C = moles C * molar mass C

mass C = 7.08 * 10^-4 mol*12.01 g/mol

mass C = 0.0085 grams

Step 7: Calculate mass of H

mass H = moles H * molar mass H

mass H = 8.86 * 10^-4 mol*1.01 g/mol

mass H = 0.000894 grams

Step 8: Calculate total mass of compound =

0.0085 grams + 0.000894 grams = 0.009394 grams = 9.394 mg

Step 9: Calculate the percent composition:  

% C = (8.50 mg / 9.394 mg) x 100 = 90.5%  

% H = (0.894 mg / 9.394 mg) x 100 = 9.5%

The percent composition of the compound is 90.5 % C and 9.5 % H

6 0
3 years ago
Ayudameeeee Jorge AhAaaAA
Gelneren [198K]
Ok what you want. I got u
5 0
2 years ago
Read 2 more answers
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