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Bumek [7]
3 years ago
5

How is conductivity related to pH?​

Chemistry
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

strongly acidic or basic solutions will have high conductivity

Explanation:

conductivity depends on the concentration of ions, and both of these extremes have a very high concentration of hydroxide or hydrogen ions

timama [110]3 years ago
3 0

Answer:

Strongly acidic [or strongly basic] solution will have high conductivity.

Explanation:

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A student chromatographs a mixture and after developing the spots with a suitable reagent he observes the following
Anika [276]

Rf value is the ratio of the distance traveled by the solute to that of the solvent front on the paper used in chromatographic separation.

From the image it is clear the distance traveled by solvent front = 7.3 cm

Distance traveled by the component -1 of the mixture = 1.4 cm

Distance traveled by the component -2 of the mixture = 3.0 cm

Distance traveled by the component -3 of the mixture = 4.5 cm

Distance traveled by the component -4 of the mixture = 6.5 cm

Rf value of component-1 = \frac{1.4 cm}{7.3 cm} =0.192

Rf value of component-2 = \frac{3.0 cm}{7.3 cm} =0.410

Rf value of component-3 = \frac{4.5 cm}{7.3 cm} =0.616

Rf value of component-4 = \frac{6.5 cm}{7.3 cm} =0.890

b) Samples can be separated from a mixture using chromatography as the relative affinities for the compounds towards the paper (stationary phase) and the solvent(mobile phase) are different. Each component spends different amounts of time on the stationary phase depending on it chemical nature. So, the components in a mixture can be separated based on their polarities and relative degrees of adsorption on the stationary phase.








6 0
3 years ago
If two gases react, pumping more gas into the reaction container will _____ the rate of the reaction.
d1i1m1o1n [39]

Answer:

increase the rate of reaction

5 0
3 years ago
Read 2 more answers
A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
kupik [55]

hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.

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6 0
3 years ago
How many particles are in 3.2 mole of neon gas
Cerrena [4.2K]

There are 1.93 x 10²⁴ particles

<h3>Further explanation</h3>

Given

3.2 moles of Neon gas

Required

Number of particles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

<em>1 mol = 6.02.10²³ particles </em>

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So the number of particles for 3.2 moles :

N = 3.2 x 6.02.10²³

N = 1.93 x 10²⁴

or

we can describe it using Avogadro's number conversion factor

\tt 3.2~moles\times \dfrac{6.02\times 10^{23}}{1~mole}=1.93\times 10^{24}

7 0
3 years ago
1. Calculate the average reaction rate expressed in moles H2 consumed per liter per second.
valentina_108 [34]

Answer:

1) 0.0025 mol/L.s.

2) 0.0025 mol/L.s.

Explanation:

  • For the reaction:

<em>H₂ + Cl₂ → 2HCl.</em>

<em></em>

<em>The average reaction rate = - Δ[H₂]/Δt = - Δ[Cl₂]/Δt = 1/2 Δ[HCl]/Δt</em>

<em></em>

<em>1. Calculate the average reaction rate expressed in moles H₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles H₂ consumed per liter per second = - Δ[H₂]/Δt = - (0.02 M - 0.03 M)/(4.0 s) = 0.0025 mol/L.s.

<em>2. Calculate the average reaction rate expressed in moles CI₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles Cl₂ consumed per liter per second = - Δ[Cl₂]/Δt = - (0.04 M - 0.05 M)/(4.0 s) = 0.0025 mol/L.s.

7 0
3 years ago
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