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vichka [17]
3 years ago
14

What is a heat pump? Why does it need to put in external work? Help ASAP!

Physics
2 answers:
pishuonlain [190]3 years ago
8 0
A heat pump is a device that puts out heat. It involves pumping a lever over and over to get energy so it can work.
Anni [7]3 years ago
6 0

Answer:

Heat pump is a device which is used to maintain the system at a temperature more than the atmospheric temperature.

<em>For example</em> if you need to maintain the system at a temperature more than the room temperature<em> (say 50° C), </em>the heat has to be supply continuously by means of supplying an external work on the system. Otherwise the heat easily escapes from the system due to temperature gradient between system and surroundings.

According to the "Thermodynamic  II law, the heat always transfer from high temperature body to low temperature body without aid of external energy, but the heat can also be transfer from low temperature body to high temperature body by means of some external energy.  

From given figure, To maintain the system at temperature 50° C, you need to do external work, because some energy always lost to the surroundings

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve ~

Given terms :

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The formula to find kinetic Energy is ~

\boxed{ \boxed{ \sf{ \frac{1}{2}  m{v}^{2} }}}

Now, apply the formula according to given situation

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2}  \times 7 \times ( {4)}^{2}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2}  \times 7 \times 16

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \times 8

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:56 \:  \: joules

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