What is a heat pump? Why does it need to put in external work? Help ASAP!
2 answers:
Answer:
Heat pump is a device which is used to maintain the system at a temperature more than the atmospheric temperature.
<em>For example</em> if you need to maintain the system at a temperature more than the room temperature<em> (say 50° C), </em>the heat has to be supply continuously by means of supplying an external work on the system. Otherwise the heat easily escapes from the system due to temperature gradient between system and surroundings.
According to the "Thermodynamic II law, the heat always transfer from high temperature body to low temperature body without aid of external energy, but the heat can also be transfer from low temperature body to high temperature body by means of some external energy.
From given figure, To maintain the system at temperature 50° C, you need to do external work, because some energy always lost to the surroundings
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Answer:
The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s
Explanation:
The momentum of the particle is related to force by the following equation:
Δp = F · Δt
Where:
Δp = change in momentum = final momentum - initial momentum
F = constant force.
Δt = time interval.
Let´s calculate the x-component of the momentum after the 0.13 s:
final momentum - 8 kg m/s = -7 N · 0.13 s
final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s
final momentum = 7.09 kg m/s
Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:
final momentum = 5 kg m/s² · 0.13 s
final momentum = 0.65 kg m/s
Then, the mometum vector will be as follows:
p = (7.09 kg m/s, 0.65 kg m/s)
The magnitude of this vector is calculated as follows:
The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s