What is a heat pump? Why does it need to put in external work? Help ASAP!
2 answers:
Answer:
Heat pump is a device which is used to maintain the system at a temperature more than the atmospheric temperature.
<em>For example</em> if you need to maintain the system at a temperature more than the room temperature<em> (say 50° C), </em>the heat has to be supply continuously by means of supplying an external work on the system. Otherwise the heat easily escapes from the system due to temperature gradient between system and surroundings.
According to the "Thermodynamic II law, the heat always transfer from high temperature body to low temperature body without aid of external energy, but the heat can also be transfer from low temperature body to high temperature body by means of some external energy.
From given figure, To maintain the system at temperature 50° C, you need to do external work, because some energy always lost to the surroundings
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Answer:
1.85 J/K
Explanation:
The computation of total change in entropy is shown below:-
Change in Entropy = Sum Q ÷ T
=
= -3.12 + 4.97
= 1.85 J/K
Therefore for computing the total change in entropy we simply applied the above formula.
As we can see that there is heat entering the reservoir so it will be negative while cold reservoir will be positive else the process would be impossible.