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solmaris [256]
3 years ago
7

From fastest to slowest, rank the speeds of the balls 1 s after being thrown. Rank the speeds of the balls from fastest to slowe

st. To rank items as equivalent, overlap them. Three balls of different masses are thrown straight upward with initial speeds as indicated: PICTURE
rank speeds
rank acclerations

Physics
2 answers:
Rus_ich [418]3 years ago
8 0

Explanation:

From the given figure,

Mass of ball A is 4.9 kg and its initial speed is 8 m/s.

Mass of ball B is 1.9 kg and its initial speed is 14 m/s.

Mass of ball C is 0.7 kg and its initial speed is 2 m/s.

We need to find the final speed of the balls 1 s after being thrown. They all are thrown upward under the action of gravity. The equation of motion is : v = u -gt, g = 10 m/s²

For ball A,

v = 8-10(1) = = -2 m/s (downward)

For B,

v = 14-10(1) = 4 m/s (upward)

For C,

v = 2-10(1) = -8 m/s (downward)

It means the ranking is B>A>C i.e. the speed of ball B is the most and that of C is least.

All the balls are moving under the action of gravity. It would mean that the acceleration for all balls is same i.e. 10 m/s²

jeka57 [31]3 years ago
6 0

Answer:

what they said

Explanation:

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Answer:

A total of 150 joules of work was done

Explanation:

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3 years ago
Find the moments of inertia Ix, Iy, I0 for a lamina that occupies the part of the disk x2 y2 ≤ 36 in the first quadrant if the d
Tasya [4]

Answer:

I(x)  = 1444×k ×{\pi}

I(y)  = 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}  

Explanation:

Given data

function =  x^2 + y^2 ≤ 36

function =  x^2 + y^2 ≤ 6^2

to find out

the moments of inertia Ix, Iy, Io

solution

first we consider the polar coordinate (a,θ)

and polar is directly proportional to a²

so p = k × a²

so that

x = a cosθ

y = a sinθ

dA = adθda

so

I(x) = ∫y²pdA

take limit 0 to 6 for a and o to \pi /2 for θ

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} y²p dA

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} (a sinθ)²(k × a²) adθda

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (sin²θ)dθ

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (1-cos2θ)/2 dθ

I(x)  = k ({r}^{6}/6)^(5)_0 ×  {θ/2 - sin2θ/4}^{\pi /2}_0

I(x)  = k × ({6}^{6}/6) × (  {\pi /4} - sin\pi /4)

I(x)  = k ×  ({6}^{5}) ×   {\pi /4}

I(x)  = 1444×k ×{\pi}    .....................1

and we can say I(x) = I(y)   by the symmetry rule

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I(o) = 2 × 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}   ......................2

3 0
3 years ago
A visible light has a wavelength of 727.3 nm. Determine its frequency, energy per photon, and color.
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Answer:

f=4.12\times 10^{14}\ Hz and E=2.73\times 10^{-19}\ J

Explanation:

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727.3\ nm=727.3 \times 10^{-9}\ m

The formula is as follows :

c=f\lambda

f is the frequency of the visible light

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{727.3 \times 10^{-9}}\\\\f=4.12\times 10^{14}\ Hz

Energy of a photon is given by :

E = hf, h is Planck's constant

E=6.63\times 10^{-34}\times 4.12\times 10^{14}\\\\E=2.73\times 10^{-19}\ J

Red color has a frequency of 4.12\times 10^{14}\ Hz and energy per photon is 2.73\times 10^{-19}\ J.

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Answer:

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Using conservation of energy

The final kinetic energy of canon depends on initial kinetic energy and potential energy.

The  final velocity depends upon initial velocity and initial height.

So,  the initial velocity of canon B is high.

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