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solmaris [256]
3 years ago
7

From fastest to slowest, rank the speeds of the balls 1 s after being thrown. Rank the speeds of the balls from fastest to slowe

st. To rank items as equivalent, overlap them. Three balls of different masses are thrown straight upward with initial speeds as indicated: PICTURE
rank speeds
rank acclerations

Physics
2 answers:
Rus_ich [418]3 years ago
8 0

Explanation:

From the given figure,

Mass of ball A is 4.9 kg and its initial speed is 8 m/s.

Mass of ball B is 1.9 kg and its initial speed is 14 m/s.

Mass of ball C is 0.7 kg and its initial speed is 2 m/s.

We need to find the final speed of the balls 1 s after being thrown. They all are thrown upward under the action of gravity. The equation of motion is : v = u -gt, g = 10 m/s²

For ball A,

v = 8-10(1) = = -2 m/s (downward)

For B,

v = 14-10(1) = 4 m/s (upward)

For C,

v = 2-10(1) = -8 m/s (downward)

It means the ranking is B>A>C i.e. the speed of ball B is the most and that of C is least.

All the balls are moving under the action of gravity. It would mean that the acceleration for all balls is same i.e. 10 m/s²

jeka57 [31]3 years ago
6 0

Answer:

what they said

Explanation:

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3 years ago
Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

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q_1 = 47.0\mu C

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by relation for electric field we have following relation

E = \frac{kq}{x}^2

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\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2

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\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}

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