From fastest to slowest, rank the speeds of the balls 1 s after being thrown. Rank the speeds of the balls from fastest to slowe
st. To rank items as equivalent, overlap them. Three balls of different masses are thrown straight upward with initial speeds as indicated: PICTURE
rank speeds
rank acclerations
rank speeds
rank acclerations
2 answers:
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Answer:
Choice a. , assuming that the skating rink is level.
Explanation:
<h3>Net force in the horizontal direction</h3>There are two horizontal forces acting on the boy:
- The pull of his friend, and
- Frictions.
The boy should be moving in the direction of the pull of his friend. The frictions on this boy should oppose that motion. Therefore, the frictions on the boy would be in the opposite direction of the pull of his friend.
The net force in the horizontal direction should then be the difference between the pull of the friend, and the friction on this boy.
.
The net force on this boy should be zero in the vertical direction. Consider Newton's Second Law of motion. The net force on an object is proportional to its acceleration. In this question, the net force on this boy in the vertical direction should be proportional to the vertical acceleration of this boy.
However, because (by assumption) the ice rink is level, the boy has no motion in the vertical direction. His vertical acceleration will be zero. As a result, the net force on him should also be zero in the vertical direction.
<h3>Net force</h3>Therefore, the (combined) net force on this boy would be:
.