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Savatey [412]
3 years ago
13

According to Newton’s first law of motion, what will an object in motion do when no external force acts on it?

Physics
2 answers:
Colt1911 [192]3 years ago
6 0

An object will continue in constant, uniform motion (in a straight
line at constant speed) until acted on by a net external force.

The speed may just as well be zero.  That covers the separate case
that people always want to add, of "an object at rest".
KonstantinChe [14]3 years ago
4 0

By definition, we have to:

Newton's first law states that any object will remain in a state of rest or with a uniform rectilinear motion unless an external force acts on it.

Therefore, according to the first law of Newton, if the object is already in motion and has no force acting on it then, it will remain with a uniform rectilinear motion.

Answer:

The object will remain with a uniform rectilinear movement when the external force does not act on it.

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A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected
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Answer:

The ball's initial kinetic energy

The ball comes to a stop at B. At this point its initial kinetic energy is converted into potential energy

Explanation:

A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.

From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.

Ki+Ui=Kf+Uf

Ki=initial kinetic energy

Ui=initial potential energy

Kf=final kinetic energy

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we know that \frac{1}{2} mu^{2} +mgha=\frac{1}{2} mv^{2} +mghb

m=mass of the ball

ha=downward height a

hb=upward height b

u=initial velocity u

v=final velocity v, which is 0

g=acceleration due to gravity

v=0 at final velocity

1/2mu^2+mgha=0+1/2mv^2

ha=hb+Ki/mh

From the above equation, we can conclude that the ball's initial kinetic energy  is responsible for making the ball reach point B.

Point B is higher than point A from the motion gained by the ball

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