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3 years ago

13

According to Newton’s first law of motion, what will an object in motion do when no external force acts on it?

2 answers:

Colt1911 [192]3 years ago

6 0

An object will continue in constant, uniform motion (in a straight
line at constant speed) until acted on by a net external force.

The speed may just as well be zero. That covers the separate case
that people always want to add, of "an object at rest".

KonstantinChe [14]3 years ago

4 0

By definition, we have to:

Newton's first law states that any object will remain in a state of rest or with a uniform rectilinear motion unless an external force acts on it.

Therefore, according to the first law of Newton, if the object is already in motion and has no force acting on it then, it will remain with a uniform rectilinear motion.

Answer:

The object will remain with a uniform rectilinear movement when the external force does not act on it.

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A cruise ship sails due south at 2.50 m/s while a coast guard patrol boat heads 19.0° north of west at 4.80 m/s. What are the x-

Nesterboy [21]

Answer:

Explanation:

We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .

velocity of cruise ship

Vcs = - 2.5 j

Vpb = - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j

velocity of the cruise ship relative to the patrol boat

= Vcs - Vpb

= - 2.5 j - ( - 4.54 i + 1.56 j )

= - 2.5 j + 4.54 i - 1.56 j

= 2.04 i - 1.56 j .

x-component of the velocity of the cruise ship relative to the patrol boat

= 2.04 m /s

y-component of the velocity of the cruise ship relative to the patrol boat

= - 1.56 m /s .

7 0

3 years ago

Integrated Science- 8th grade science

padilas [110]

Answer:

A. a rigorously tested explanation

Explanation:

B. and D. are out - theories are not opinionated, they are factual
C. is out - not all theories are mathematical
A. is the best choice

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2 years ago

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fredd [130]

Because noble gases has full of 8 electron in her external cell......

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What are the different isotopes

Norma-Jean [14]

Answer:

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Explanation: not sure if more was supposed to be there, but i tried

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3 years ago

A filamentary conductor is formed into an equilateral triangle with sides of length carrying current i . find the magnetic field

arsen [322]

magnetic field due to a finite straight conductor is given by

$B = \frac{\mu_0 i}{4\pi r}(sin\theta_1 + sin\theta_2)$

here since it forms an equilateral triangle so we will have

$\theta_1 = \theta_2 = 60 degre$

also the perpendicular distance of the point from the wire is

$r = \frac{a}{2\sqrt3}$

now from the above equation magnetic field due to one wire is given by

$B = \frac{\mu_0 i}{4\pi \frac{a}{2\sqrt3}(sin60 + sin60)$

$B = \frac{\mu_0 i*2\sqrt3}{4\pi a}(\sqrt3)$

$B = \frac{3\mu_0 i}{2\pi a}$

now since in equilateral triangle there are three such wires so net magnetic field will be

$B = \frac{9\mu_0 i}{2\pi a}$

5 0

3 years ago