3 years ago

A student pushes a book with a force of 5 N to the east.which statement

Physics

1 answer:

natulia [17]3 years ago

8 0

Answer:

5N westward, acting on the student

Explanation:

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How do the different forms of potential energy depend on an object's position or chemical composition?

devlian [24]

It depends on the objects chemical composition.

6 0

2 years ago

A Perspex container has a 6 cm square base and contains

crimeas [40]

Answer:

a) V = 252 cm³

b) Vs = 72 cm³

Explanation:

The volume of the water can be given by the following formula:

$Volume\ of\ Water = V = (Base\ Area)(Height)\\V = (Length)^2(Height)\\V = (6\ cm)^2(7\ cm)\\$

V = 252 cm³

The volume of stone can be given by the change in volume of the water when the stone is dipped into it.

$Volume\ of\ Stone = Vs = (Length)^2(Change\ in\ Height\ of\ Water)\\Vs = (6\ cm)^2(9\ cm - 7\ cm)\\$

Vs = 72 cm³

6 0

3 years ago

to what height will a 250g soccer ball rise to if it is kicked directly upwards at 8 meters per second

Nonamiya [84]

Answer:

3.2 m

Explanation:

we know

Hmax = V²/2g

= 8² / 2*10 = 3.2

6 0

3 years ago

Read 2 more answers

If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high

kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

E = hf...where E(is the energy of a photon);h(is the planck's constant) and f is the frequency of the photon

Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

3 0

3 years ago

A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300

IrinaVladis [17]

Answer:

The bottom of the sea is 25 m below sea level.

Explanation:

Given data

Mass = 6.1 × $10^{8} \ kg$

$\rho_{sea} = 1020\ \frac{kg}{m^{3} }$

We know that Buoyant force on the tank is equal to gravity force of the tank.

$F_B = F_g$

$(\rho_{Fluid}) (g) (V_{disp}) = m g$

$(\rho_{Fluid}) (V_{disp}) = m$

1020 × $V_{disp}$ = 6.1 × $10^{8}$

$V_{disp}$ = 598039.21 $m^{3}$

We know that

$V_{disp}$ = W × L × H

598039.21 = 300 × 80 × H

H = 25 m

Therefore the bottom of the sea is 25 m below sea level.

7 0

3 years ago