2.) dT/dt = -t^2 + 3t
dT = (-t^2 + 3t)dt
T = -t^3/3 + 3t^2/2 + C
at 4:00 AM
80 = -4^3/3 + 3*4^2/2 + C
C = 80 + 4^3/3 - 3*4^2/2
C = 77.33
T = -t^3/3 + 3t^2/2 + 77.33
at 8:00 AM
T = -8^3/3 + 3*8^2/2 + 77.33
T = 2.67 deg
Answer:
its d
2.52x
3.40
____
0.00+
1.080+
7.5600
______.
8.658
