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3 years ago

PLEASE ANSWER ALL 5 OF THESE QUESTIONS. PLEASE PLEASE NO FAKE ANSWERS AND I NEED HELP AND FAST.

Mathematics

2 answers:

Nana76 [90]3 years ago

6 0

The first one is graph 2 because he builds nearly no speed, drops to zero and then starts up again
the second one is graph 3 because rider had consistent speed then slowed down at a marked point
the third one is graph 1 because slow building and then to constant

I've never seen a type of question like 4 and 5.
Sorry this is all the help that I can be.

kiruha [24]3 years ago

4 0

the first one is graph two

The second one is graph 3 because he didn't stop he slowed down.

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Carmen received a gift of $5,000 from her grandmother and decided to invest it. the expression 5000(1.0005)^12t represents the a

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The equivalent expression for the expression that represents the amount Carmen would earn is 5000(1.0005^12)^t.

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Based on the expression given, Carmen's investment is compounded monthly.

The formula for calculating future value:

FV = P (1 + r)^nm

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5000(1.0005)^12t

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50002.5^12t

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1 year ago

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)

beks73 [17]

H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m

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