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Sav [38]
4 years ago
13

Two balls are placed near one another and hang down, as

Chemistry
1 answer:
Makovka662 [10]4 years ago
6 0

Answer:

A

Explanation:

If B) - the balls would be moved apart

If C) - the balls would be moved close to each other.

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Liquid helium boils at –268.93 °C. What is the boiling point of helium on the Kelvin temperature scale?
BARSIC [14]

In order to change celcius to kelvin always add 73 to it leaving you with -195.93

4 0
3 years ago
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A student investigates the properties of an unknown liquid substance in a beaker. The student finds the substance has a mass of
shtirl [24]

Answer:

The substance is a mixture because it left a white powder in the beaker when boiled.

Explanation:

8 0
3 years ago
4.Calculate the volume of 40g of Helium (He) at rtp.
Oksana_A [137]

Answer:

2.24dm³

Explanation:

Given parameters:

Mass of He = 40g

Unknown:

Volume of Helium  = ?

Solution:

To solve this problem, we convert the given mass to number of moles.

   Number of moles  = \frac{mass}{molar mass}  

   molar mass of He  = 4g/mol

  Number of moles  = \frac{4}{40}   = 0.1mole

So;

                  1 mole of gas at rtp occupies a volume of 22.4dm³

                0.1 mole of He will occupy a volume of 0.1 x 22.4 = 2.24dm³

4 0
3 years ago
Why is creativity important in science?
nasty-shy [4]
Because you need to know how/ learn to try new things for (new experiments) and creativity will teach you different ways on how to do it.
4 0
3 years ago
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Effective nuclear charge, Zeff, is defined as:
Alborosie

Answer:

The effective nuclear charge for a valence electron in oxygen atom: Z_{eff} = 4.55

Explanation:

Effective nuclear charge  [Z_{eff}] is the net nuclear charge experienced by the electron in a given atom. It is always less than the actual charge of the nucleus [Z], due to shielding by electrons in the inner shells.

<em>It is equal to the difference between the actual nuclear charge or the atomic number (Z) and the shielding constant (s).  </em>

\Rightarrow Z_{eff} = Z - s

<u>For an oxygen atom</u>-

Electron configuration: (1s²) (2s² 2p⁴)

<em>The atomic number (actual nuclear charge): </em>Z = 8

The shielding constant (s) for a valence electron can be calculated by using the Slater's rules:

⇒ s = 5 × 0.35 + 2 × 0.85 = 1.75 + 1.7 = 3.45

<u><em>Therefore, the effective nuclear charge for a valence electron in oxygen atom is:</em></u>

Z_{eff} = Z - s = 8 - 3.45 = 4.55

<u>Therefore, the effective nuclear charge for a valence electron in oxygen atom:</u> Z_{eff} = 4.55

6 0
3 years ago
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