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4 years ago

What is the expected product when l-propanol is oxidized?

Chemistry

2 answers:

kotykmax [81]4 years ago

5 0

Answer:

propanoic acid

Explanation:

One of the properties of alkanols is the fact that they can be oxidized to various products depending on the structure of the alkanol.

A primary alkanol (such as 1-propanol) is oxidized to an alkanal and subsequently to an alkanoic acid.

A secondary alkanol is oxidized to an alkanone while a tertiary alkanol is not oxidized.

This implies that the final product of the oxidation of 1-propanol is propanoic acid as shown in the answer.

IRINA_888 [86]4 years ago

4 0

Answer: propanal and propanoic acid

Explanation: first of all Oxidation of alcohol with mild oxidizing reagent PCC gives Carbonyl compounds and with strong oxidizing agent like CrO3 and kmno4 gives carboxylic acids.

And primary alcohol gives Aldehyde with mild oxidizing reagent and carboxylic acids with strong oxidizing agent.

And ketone is formed with secondary alcohol by both mild and strong Oxidizing agent.

Here our compound is primary alcohol hence we will get propanal and propanoic acid depending on type of Oxidizing agent

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The coefficient of thermal expansion α = (1/V)(∂V/∂T)p. Using the equation of state, compute the value of α for an ideal gas. Th

andreyandreev [35.5K]

Answer:

The coefficient of thermal expansion α is

$\alpha = \frac{1}{T}$

The coefficient of compressibility

$\beta = \frac{1}{P}$

Now considering $(\frac{ \delta P }{\delta T} )V$

From equation (1) we have that

$\frac{ \delta P}{\delta T} = \frac{n R }{V}$

From ideal equation

$nR = \frac{PV}{T}$

$\frac{\delta P}{\delta T} = \frac{PV}{TV}$

=> $\frac{\delta P}{\delta T} = \frac{P}{T}$

=> $\frac{\delta P}{\delta T} = \frac{\alpha }{\beta}$

Explanation:

From the question we are told that

The coefficient of thermal expansion is $\alpha = \frac{1}{V} * (\frac{\delta V}{ \delta P}) P$

The coefficient of compressibility is $\beta = - (\frac{1}{V} ) * (\frac{\delta V}{ \delta P} ) T$

Generally the ideal gas is mathematically represented as

$PV = nRT$

=> $V = \frac{nRT}{P} --- (1)$

differentiating both side with respect to T at constant P

$\frac{\delta V}{\delta T } = \frac{ n R }{P}$

substituting the equation above into $\alpha$

$\alpha = \frac{1}{V} * ( \frac{ n R }{P}) P$

$\alpha = \frac{nR}{PV}$

Recall from ideal gas equation $T = \frac{PV}{nR}$

$\alpha = \frac{1}{T}$

Now differentiate equation (1) above with respect to P at constant T

$\frac{\delta V}{ \delta P} = -\frac{nRT}{P^2}$

substituting the above equation into equation of $\beta$

$\beta = - (\frac{1}{V} ) * (-\frac{nRT}{P^2} ) T$

$\beta =\frac{ (\frac{n RT}{PV} )}{P}$

Recall from ideal gas equation that

$\frac{PV}{nRT} = 1$

$\beta = \frac{1}{P}$

Now considering $(\frac{ \delta P }{\delta T} )V$

From equation (1) we have that

$\frac{ \delta P}{\delta T} = \frac{n R }{V}$

From ideal equation

$nR = \frac{PV}{T}$

$\frac{\delta P}{\delta T} = \frac{PV}{TV}$

=> $\frac{\delta P}{\delta T} = \frac{P}{T}$

=> $\frac{\delta P}{\delta T} = \frac{\alpha }{\beta}$

5 0

3 years ago

Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

ICE Princess25 [194]

Answer:

Explanation:

Given data:

Moles of Cl₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

C : Cl₂

3 : 4

4.55 : 4/3×4.55 = 6.1 mol

6.1 moles of chlorine will react with 4.55 moles of C.

Given data:

Mass of TiO₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

C : TiO₂

3 : 2

4.55 : 2/3×4.55 = 3 mol

Mass of TiO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 79.87 g/mol

Mass = 239.61 g

Given data:

Molecules of TiCl₄ formed = ?

Moles of TiO₂ react = 115 g

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Number of moles of TiO₂:

Number of moles = mass/ molar mass

Number of moles = 115 g/ 79.87 g/mol

Number of moles = 1.44 mol

Now we will compare the moles of Cl₂ with C.

TiO₂ : TiCl₄

2 : 2

1.44 : 1.44

Molecules of TiCl₄:

1 mole = 6.022 × 10²³ molecules

1.44 ×6.022 × 10²³ molecules

8.672× 10²³ molecules

8 0

4 years ago

Generally, as you go down a group in the period ic table, what happens to atomic radius and IE?

aev [14]

Answer:

Atomic radius increased from top to bottom in group with increase of atomic number. while ionization energy decreased.

Explanation:

Definition of atomic radii:

The atomic radius is the distance between center of two similar bonded atoms.

Ionization energy:

The amount of energy required to remove the outer most electron from gaseous atom.

Trend along group:

In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number. As the atomic number increased one more electron is added and because of this electron on more electronic shell is added. Thus the outer most shell becomes further away from the nucleus and hold of nucleus becomes weaker. Although nuclear charge is also increased but at the same time atomic size also increased and addition of electrons create shielding effect, thus it is easy to remove the electron and in this way ionization energy decreased from to to bottom.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.

7 0

4 years ago

Why can't the position of an electron be determined with certainty?

iVinArrow [24]

The speed of the electron is so high that by the time we define some position it moves to other position

6 0

4 years ago

Which of the following statements is true?

Paladinen [302]

Answer:

a chromosome contains many genes

Explanation:

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3 years ago