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4 years ago

What is the expected product when l-propanol is oxidized?

Chemistry

2 answers:

kotykmax [81]4 years ago

5 0

Answer:

propanoic acid

Explanation:

One of the properties of alkanols is the fact that they can be oxidized to various products depending on the structure of the alkanol.

A primary alkanol (such as 1-propanol) is oxidized to an alkanal and subsequently to an alkanoic acid.

A secondary alkanol is oxidized to an alkanone while a tertiary alkanol is not oxidized.

This implies that the final product of the oxidation of 1-propanol is propanoic acid as shown in the answer.

IRINA_888 [86]4 years ago

4 0

Answer: propanal and propanoic acid

Explanation: first of all Oxidation of alcohol with mild oxidizing reagent PCC gives Carbonyl compounds and with strong oxidizing agent like CrO3 and kmno4 gives carboxylic acids.

And primary alcohol gives Aldehyde with mild oxidizing reagent and carboxylic acids with strong oxidizing agent.

And ketone is formed with secondary alcohol by both mild and strong Oxidizing agent.

Here our compound is primary alcohol hence we will get propanal and propanoic acid depending on type of Oxidizing agent

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Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0

podryga [215]

<u>Answer:</u> The concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

<u>Explanation:</u>

We are given:

Concentration of $AlBr_3$ = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

$AlBr_3\rightarrow Al^{3+}+3Br^-$

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions = $[(3\times 0.1)]=0.3M$

Hence, the concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

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3 years ago

If the unknown elements on the periodic table are "unknown" how did they end up in the periodic table in the first place? *think

mezya [45]

Answer:

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Explanation:

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4 years ago

9. Sodium reacts with water to produce sodium hydroxide and hydrogen gas, as shown below.

saveliy_v [14]

Answer:

Explanation:

2Na + 2H2O2==NaOh + H2

184/23=x/18

x=(184×18)/23

x=144g

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