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Alekssandra [29.7K]
3 years ago
5

The pressure inside a pressure cooker is 2.0 atm. How many minutes will it take to cook 1.0 pound of potatoes in a pressure cook

er if it takes 45 minutes to cook them in boiling water at standard pressure? Given: volume of the pressure cooker is 4.0L, there are 0.25 gaseous moles, and E_a​ = 1.77 x 10^55 J/mol.

Chemistry
1 answer:
suter [353]3 years ago
8 0

Answer:

time taken to cook on the pressure cooker = 100 seconds = 1.67 mins

Explanation:

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A gas mixture is composed of three different gases. The first gas in the mixture has a pressure of 0.35 atm. The second gas in t
riadik2000 [5.3K]

Answer:

1.20atm

Explanation:

Given parameters:

Partial pressure of gas 1 = 0.35atm

Partial pressure of gas 2  = 0.20atm

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Unknown:

Total pressure of the gas mixture = ?

Solution:

To solve this problem, we need to recall and understand the Dalton's law of partial pressure.

Dalton's law of partial pressure states that "the total pressure of a mixture of gases is equal to the sum of the partial pressure of the constituent gases".

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The partial pressure is the pressure a gas would exert if it alone occupied the volume of the gas mixture.

     

Now we substitute;

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FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

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emmainna [20.7K]

Answer:

False

Explanation:

youre welcome

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