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Leno4ka [110]
2 years ago
12

Determine moles of 1.5g of sodium carbonate.

Chemistry
1 answer:
KIM [24]2 years ago
8 0

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = \frac{1.5}{106}   = 0.014mol

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Which one of these is an example of a virus that can affect a range of hosts? A) the varicella virus B) the rabies virus C) the
Sedaia [141]

Answer:

B) the rabies viru

Explanation:

5 0
2 years ago
How many equivalents are present in 10 g of Ca2+? <br> 1 <br> 0.5 <br> 1.5 <br> 2
Lynna [10]

0.5

Explanation:

Given parameters:

Mass of Ca²⁺ = 10g

unknown:

Equivalent weight = ?

Solution:

Equivalent weight that is the amount of electrons which a substance gains or loses per mole.

Ca²⁺ has +3 charge

It lost 2e⁻;

therefore;

  In 1 mole of  Ca²⁺, we have 2 equivalent weight

1 mol  Ca²⁺ = 2eq. wts. 

1 mol Ca x (40 g / 1 mol ) x (1 mol / 2 eq.wts.) = 20.0 g = 1 eq.wt. 

Therefore;

10.0 g  Ca²⁺ x (1 eq.wt. / 20.0 g) = 0.5 eq.wts.

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

8 0
3 years ago
A pound of margarine costs $1.39. What is the cost of a kilogram of margarine
den301095 [7]

Answer:

              3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

                                    1 Kilogram  = 2.20462 Pounds

Hence, as given,

                        1 Pound of Margarine costs  =  1.39 Dollars

So,

                  2.20462 Pounds Margarine will cost  =  X Dollars

Solving for X,

                     X  =  (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

                     X =  3.064 Dollars

8 0
2 years ago
Tetrachloromethane, CCl4 is produced from the substitution reaction between methane and chlorine gas. If the rate of formation o
Korolek [52]

The rate of disappearance of chlorine gas : 0.2 mol/dm³

<h3>Further explanation</h3>

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

For reaction :

\tt aA+bB\rightarrow cC+dD

The rate reaction :

\tt -\dfrac{1}{a}\dfrac{d[-A]}{dt}= -\dfrac{1}{b}\dfrac{d[-B]}{dt}=\dfrac{1}{c}\dfrac{d[C]}{dt}=\dfrac{1}{d}\dfrac{d[D]}{dt}

Reaction for formation CCl₄ :

<em>CH₄+4Cl₂⇒CCl₄+4HCl</em>

<em />

From equation, rate of reaction = rate of formation CCl₄ = 0.05 mol/dm³

Rate of formation of  CCl₄  = reaction rate x coefficient of  CCCl₄

0.05 mol/dm³ = reaction rate x 1⇒reaction rate = 0.05 mol/dm³

The rate of disappearance of chlorine gas (Cl₂) :

Rate of disappearance of  Cl₂  = reaction rate x coefficient of  Cl₂

Rate of disappearance of  Cl₂ = 0.05 x 4 = 0.2 mol/dm³

4 0
3 years ago
All of the following methods would increase the solubility of a solid solute, except for
cricket20 [7]
May i please have a(n) answer choices please because it would be a lot better if it was like that and then ill answer it
8 0
3 years ago
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