The properties of the given elements are as follows:
Potassium, K;
- State of matter: Solid
- Melting point: 63.5 °C
- Conductivity: Good
- Solubility (H2O): reacts rapidly with water
Iodine, I;
- State of matter: solid
- Melting point: 113.5 °C
- Conductivity: very poor
- Solubility (H2O): negligible
Gold, Au;
- State of matter: solid
- Melting point: 1064 °C
- Conductivity: excellent
- Solubility (H2O): none
Germanium, Ge;
- State of matter: solid
- Melting point: 938.2 °C
- Conductivity: fair
- Solubility (H2O): none
Barium, Ba;
- State of matter: solid
- Melting point: 727 °C
- Conductivity: good
- Solubility (H2O): reacts strongly
Argon, Ar;
- State of matter: gas
- Melting point: -189.4 °C
- Conductivity: none
- Solubility (H2O): negligible
Chlorine Cl;
- State of matter: gas
- Melting point: -101.5 °C
- Conductivity: poor
- Solubility (H2O): slight
Rubidium, Rb;
- State of matter: solid
- Melting point: 39.48 °C
- Conductivity: good
- Solubility (H2O): reacts violently
Silver, Ag;
- State of matter: solid
- Melting point: 961.8 °C
- Conductivity: excellent
- Solubility (H2O): none
Calcium, Ca;
- State of matter: solid
- Melting point: 842 °C
- Conductivity: good
- Solubility (H2O): reacts
Silicon, Si;
- State of matter: solid
- Melting point: 1,410 °C
- Conductivity: intermediate
- Solubility (H2O): none
Xenon, Xe;
- State of matter: gas
- Melting point: -111.8 °C
- Conductivity: very poor
- Solubility (H2O): none
<h3>What are elements?</h3>
Elements are pure substances which are composed of similar atoms.
Elements are defined as substances which cannot be split into simpler substances by an ordinary chemical process.
Elements have different physical and chemical properties and can be classified into:
- metals
- semi-metals
- non-metals
In conclusion, the physical and chemical properties of the elements vary from metals to non-metals.
Learn more about elements at: brainly.com/question/6258301
#SPJ1
The volume of H₃PO₄ : 13.33 ml
<h3>Further explanation</h3>
Given
0.003 M Phosphoric acid-H₃PO₄
40 ml of 0.00150 M Calcium hydroxide-Ca(OH)₂
Required
Volume of H₃PO₄
Solution
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence (amount of H⁺/OH⁻)
H₃PO₄⇒3H⁺ + PO₄³⁻ ⇒ 3 H⁺ = valence = 3
Ca(OH)₂⇒Ca²⁺ + 2OH⁻⇒ 2 OH⁻ = valence = 2
Input the value :
a = H₃PO₄, b = Ca(OH)₂
0.003 x Va x 3 = 0.0015 x 40 x 2
Va = 13.33 ml
Balance Chemical equation is as follow,
<span> 3 H</span>₂ <span>(g) + N</span>₂ <span>(g) </span>→<span> 2 NH</span>₃ <span>(g)
According to balanced equation, 3 Molecules (3 moles) of Hydrogen reacts with 1 Molecule of N</span>₂ to produce 2 moles (2 Molecules) of NH₃.
Result:
2 Molecules of Ammonia are produced by reacting 3 molecules of Hydrogen and 1 molecule of Nitrogen.
Answer:
This solution is quite lengthy
Total system = nRT
n was solved to be 0.02575
nH20 = 0.2x0.02575
= 0.00515
Nair = 0.0206
PH20 = 0.19999
Pair = 1-0.19999
= 0.80001
At 15⁰c
Pair = 0.4786atm
I used antoine's equation to get pressure
The pressure = 0.50
2. Moles of water vapor = 0.0007084
Moles of condensed water = 0.0044416
Grams of condensed water = 0.07994
Please refer to attachment. All solution is in there.
Hey there!:
Molar mass H3PO4 = <span>97.9952 g/mol
Atomic Masses :
H = </span><span>1.00794 a.m.u
</span>P = <span>30.973762 a.m.u
</span>O = 15.9994 a.m.u<span>
H % = [ ( 1.00794 * 3 ) / </span> 97.9952 ] * 100
H% = <span>3.0857 %
P % = [ ( </span>30.973762 * 1 ) / 97.9952 ] * 100
P% = <span>31.6074 %
O % = [ ( </span>15.9994 * 4 ) / 97.9952 ] * 100
O% = <span>65.3069 %
Hope this helps!</span>
