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GrogVix [38]
3 years ago
10

How many square centimeters are in an area of 8.10inch2 ?

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0
8.10in^2=52.25796cm^2

1 in^2=6.4516cm^2

8.10in^2*6.4516cm^2/1 in^2

8.10in^2*6.4516cm^2= 52.25796 cm^2
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3.5 mg of optically-enriched (-) sugar P was dissolved in 1.00 mL methanol in a 1.00 mL volumetric flask. The optical rotation w
denpristay [2]

Answer:

cell progressnya ia active the volume

3 0
4 years ago
A sample of nitric acid has a mass of 8.2g. It is dissolved in 1L of water. A 25mL aliquot of this acid is titrated with NaOH. T
AveGali [126]

Answer:

18.075 mL of NaOH solution was added to achieve neutralization

Explanation:

First, let's formulate the chemical reaction between nitric acid and sodium hydroxide:

NaOH + HNO3 → NaNO3 + H2O

From this balanced equation we know that 1 mole of NaOH reacts with 1 mole of HNO3 to achieve neutralization. Let's calculate how many moles we have in the 25 mL aliquot to be titrated:

63.01 g of HNO3 ----- 1 mole

8.2 g of HNO3 ----- x = (8.2 g × 1 mole)/63.01 g = 0.13014 moles of HNO3

So far we added 8.2 grams of nitric acid (0.13014 moles) in 1 L of water.

1000 mL solution ---- 0.13014 moles of HNO3

25 mL (aliquot) ---- x = (25 mL× 0.13014 moles)/1000 mL = 0.0032535 moles

So, we now know that in the 25 mL aliquot to be titrated we have 0.0032535 moles of HNO3. As we stated before, 1 mole of NaOH will react with 1 mole of HNO3, hence 0.0032535 moles of HNO3 have to react with 0.0032535 moles of NaOH to achieve neutralization. Let's calculate then, in which volume of the given NaOH solution we have 0.0032535 moles:

0.18 moles of NaOH ----- 1000 mL Solution

0.0032535 moles---- x=(0.0032535moles×1000 mL)/0.18 moles = 18.075mL

As we can see, we need 18.075 mL of a 0.18 M NaOH solution to titrate a 25 mL aliquot of the prepared HNO3 solution.

4 0
3 years ago
What is this process of producing more offspring than possibly survive called?
tamaranim1 [39]

Darwin's Theory of Evolution by Natural Selection.

Darwin divided this theory into multiple parts but overall it fits into Darwin's Theory of Evolution by Natural Selection, so that would be your answer.

In case you're wondering about the others:

1. Organisms produce more offspring than actually survive.

2. Every organism must struggle to survive.

3. There is variation within a species.

4. Some variations allow members of a species to survive and reproduce better than others.

5. Organisms that survive and reproduce pass their traits to their offspring, and the helpful traits gradually appear in more and more of the population.

(these are brief explanations, they go into more detail)

Good luck!

4 0
3 years ago
Number of molecules of carbon dioxide in 880 grams of carbon dioxide will<br> be..?
mr Goodwill [35]

Answer:

1 grams Carbon Dioxide = 0.022722366761722 mole using the molecular weight calculator and the molar mass of CO2.

Explanation:

its a starter

6 0
3 years ago
A solution is prepared by dissolving 4.66 g of KCl in enough distilled water to give 250 mL of solution. KCl is a strong electro
Leokris [45]

Answer:

Depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

Explanation:

On adding any non volatile solute to a solvent its boiling point increases and its freezing point decreases [these are two of the four colligative properties].

The depression in freezing point is related to molality of solution as:

ΔTf=iK_{f}Xmolality

where

ΔTf= depression in freezing point

Kf= cryoscopic constant of water = 1.853 K. kg/mol.

i = Van't Hoff factor = 2 ( for KCl)

molality = \frac{molesofsolute}{massofsolvent(Kg)}

moles of solute = mass / molarmass = 4.66 / 74.55 =0.0625

mass of solvent = mass of solution (almost)

considering the density of solution to be 1g/mL

mass of solvent = 250 grams = 0.250 Kg

molality = \frac{0.0625}{0.25}= 0.25

Putting values

depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

7 0
4 years ago
Read 2 more answers
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