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pychu [463]
3 years ago
15

Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

Explanation:

1)

Given data:

Moles of Cl₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

                         C             :            Cl₂

                         3             :              4

                       4.55         :            4/3×4.55 = 6.1 mol

6.1 moles of chlorine will react with 4.55 moles of C.

2)

Given data:

Mass of TiO₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

                         C             :            TiO₂

                         3             :              2

                       4.55         :            2/3×4.55 = 3 mol

Mass of TiO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 79.87 g/mol

Mass =  239.61 g

3)

Given data:

Molecules of TiCl₄ formed = ?

Moles of TiO₂ react = 115 g

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Number of moles of TiO₂:

Number of moles = mass/ molar mass

Number of moles = 115 g/ 79.87 g/mol

Number of moles = 1.44 mol

Now we will compare the moles of Cl₂ with C.

                      TiO₂           :            TiCl₄

                         2             :              2

                       1.44           :            1.44

Molecules of TiCl₄:

1 mole = 6.022 × 10²³ molecules

1.44 ×6.022 × 10²³ molecules

8.672× 10²³ molecules

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Serjik [45]

Answer:

A

Explanation:

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6 0
3 years ago
For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
Sindrei [870]

Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

x = mass extracted

m = total mass of solute

K = distribution coefficient

Vo = volume of organic layer

Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then  

r = m(0.382)^n.

If n = 7,

r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

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5 0
3 years ago
HELPP! pls
pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  \frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}

or,

⇒  Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr

⇒                      =\frac{1}{2}\times 4.96

⇒                      =2.48 \ mole

(b)

The limiting reactant is:

= HBr

(c)

The excess reactant is:

= Al

6 0
2 years ago
Matter can exist as a solid, a liquid, or a gas. The solid state is distinguished by its ability to
Elina [12.6K]

Answer:

D

Explanation:

A solid is characterized by structural rigidity and resistance to a force applied to the surface. Unlike a liquid, a solid object does not flow to take on the shape of its container, nor does it expand to fill the entire available volume like a gas. Solids molecules stay close to eachother maintaining its shape meaning it is in a ordered pattern.

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