Question

Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

Answer 1

Answer:

Explanation:

1)

Given data:

Moles of Cl₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

                         C             :            Cl₂

                         3             :              4

                       4.55         :            4/3×4.55 = 6.1 mol

6.1 moles of chlorine will react with 4.55 moles of C.

2)

Given data:

Mass of TiO₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

                         C             :            TiO₂

                         3             :              2

                       4.55         :            2/3×4.55 = 3 mol

Mass of TiO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 79.87 g/mol

Mass =  239.61 g

3)

Given data:

Molecules of TiCl₄ formed = ?

Moles of TiO₂ react = 115 g

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Number of moles of TiO₂:

Number of moles = mass/ molar mass

Number of moles = 115 g/ 79.87 g/mol

Number of moles = 1.44 mol

Now we will compare the moles of Cl₂ with C.

                      TiO₂           :            TiCl₄

                         2             :              2

                       1.44           :            1.44

Molecules of TiCl₄:

1 mole = 6.022 × 10²³ molecules

1.44 ×6.022 × 10²³ molecules

8.672× 10²³ molecules