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Elena L [17]
2 years ago
8

An architectural drawing lists the scale as 1/4" = 1'. If a bedroom measures 3 1/2" by 5 1/4" on the drawing, how large is the b

edroom?
A. 20 ft by 30 ft
B. 7ft by 10.5 ft
C. 14 ft by 21 ft
D. 10 ft by 15 ft
Mathematics
1 answer:
Alla [95]2 years ago
7 0

Answer:

C. 14 ft by 21 ft

Step-by-step explanation:

First you want to set up an equation:

3 1/2" over x' = 1/4" over 1'

7/2 = 1/4x

14' = x

Next, do the same thing for the other side of the drawing (5 1/4")

5 1/4" over y' = 1/4" over 1'

21/4 = 1/4y

21' = y

So the answer is 14 ft by 21 ft (C)

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\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
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x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)



\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
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(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\

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There's one more condition I forgot about
-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\

Finally
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\boxed{\boxed{x=1}}
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