Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Answer:
5t-4n+2
Step-by-step explanation:
n-5n=-4n
5t-4n+2
Answer:
The expression which is equivalent to –2i(6 – 7i) is; (0 – 2i)(6 – 7i)
Answer:
ok give me a min
Step-by-step explanation: