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Nady [450]
3 years ago
15

At equilibrium, a 1.0 L reaction vessel contains 2.3 mol of Mg(OH)₂ and 0.170 mol of OH⁻. What is the equilibrium concentration

of Mg²⁺ based on the reaction:
Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq) Kc = 1.80 x 10⁻¹¹
Chemistry
1 answer:
Andru [333]3 years ago
7 0

The value of X for this chemical reaction is 1.65 x 10⁻⁴

<u>Explanation:</u>

Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)  

Kc= 1.80x10⁻¹¹

KC = [Mg²⁺][OH-]²

Let us assume

Put X = [Mg²⁺] and  2x = [OH-]

1.80x10-11 = (X) (2X)²

1.80x10-11 = 4X³

X³ = 4.5x10⁻¹²

On simplifying the equation we get,

X = 1.65 x 10⁻⁴

The value of X for this chemical reaction is 1.65 x 10⁻⁴

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Five liters of air at -35°C is warmed to 89°C. What is the new volume if the pressure remains constant
Delicious77 [7]

Answer:

7.61 liters

Explanation:

From the question,

Applying Charles law formula,

V₁/T₁ = V₂/T₂...................... Equation 1

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make V₂ the subject of the equation

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Answer:

From 4.0 moles of hydrogen 2.67 moles of ammonia are produced.

Explanation:

Given data:

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Number of moles of ammonia produced = ?

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