At equilibrium, a 1.0 L reaction vessel contains 2.3 mol of Mg(OH)₂ and 0.170 mol of OH⁻. What is the equilibrium concentration

Question

3 years ago

15

of Mg²⁺ based on the reaction:
Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq) Kc = 1.80 x 10⁻¹¹

1 answer:

Andru [333] · Answer 1 · 2022-09-06T07:56:40+03:00

The value of X for this chemical reaction is 1.65 x 10⁻⁴

<u>Explanation:</u>

Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)

Kc= 1.80x10⁻¹¹

KC = [Mg²⁺][OH-]²

Let us assume

Put X = [Mg²⁺] and 2x = [OH-]

1.80x10-11 = (X) (2X)²

1.80x10-11 = 4X³

X³ = 4.5x10⁻¹²

On simplifying the equation we get,

X = 1.65 x 10⁻⁴

The value of X for this chemical reaction is 1.65 x 10⁻⁴