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3 years ago

What is Avogadro's number?

Chemistry

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

C. the number of atoms, molecules, ions, formula units, or other particles in a mole of a substance

Explanation: Its correct

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Recall the postulates of kinetic-molecular theory.

son4ous [18]

This theory<span> is based on the following </span>postulates<span>, or </span>assumptions<span>. Gases are composed of a large number of particles that behave like hard, spherical objects in a state of constant, random motion. These particles move in a straight line until they collide with another </span>particle<span> or the walls of the container.

hope this helps, if you need more, im here to help!</span>

8 0

4 years ago

Determine the poh of 0.01 molar solution of carbonic acid

Veronika [31]

Hello!

Data:

Molar Mass of H2CO3 (carbonic acid)

H = 2*1 = 2 amu

C = 1*12 = 12 amu

O = 3*16 = 48 amu

------------------------

Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol

Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:

M (molarity) = 0.01 M (Mol/L) → $1*10^{-2}\:M$

Use: Ka (ionization constant) = $4.4*10^{-7}$

$\alpha^2 (degree\:of\:ionization) = ?$

$Ka = M * \alpha^2$

$4.4*10^{-7} = 1*10^{-2}*\alpha^2$

$1*10^{-2}*\alpha^2 = 4.4*10^{-7}$

$\alpha^2 = \dfrac{4.4*10^{-7}}{1*10^{-2}}$

$\alpha^2 = 4.4*10^{-7-(-2)}$

$\alpha^2 = 4.4*10^{-7+2}$

$\alpha^2 = 4.4*10^{-5}$

$\alpha = \sqrt{4.4*10^{-5}}$

$\boxed{\alpha \approx 2.09*10^{-5}}$

Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:

$[ H_{3} O^+] = M* \alpha$

$[ H_{3} O^+] = 1*10^{-2}* 2.09*10^{-5}$

$[ H_{3} O^+] = 2.09*10^{-2-5}$

$\boxed{[ H_{3} O^+] = 2.09*10^{-7}}$

And finally, we will use the data found and put in the logarithmic equation of the PH, thus:

Data:

$pH = \:?$

$[ H_{3} O^+] = 2.09*10^{-7}$

apply the data to formula

$pH = - log[H_{3} O^+]$

$pH = - log[2.09*10^{-7}]$

$pH = 7 - log\:2.09$

$pH = 7 - 0.32$

$\boxed{pH = 6.68}$

Note:. The pH <7, then we have an acidic solution (weak acid).

Now, let's find pOH by the following formula:

$pH + pOH = 14$

$6.68 + pOH = 14$

$pOH = 14 - 6.68$

$\boxed{\boxed{pOH = 7.32}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

3 0

3 years ago

Which of the following is the correct definition of "weathering"? *

AnnyKZ [126]

I think that it would be the breakdown. Hope this helps!

5 0

3 years ago

Read 2 more answers

Calcium propionate [Ca(CH₃CH₂COO)₂; calcium propanoate] is a mold inhibitor used in food, tobacco, and pharmaceuticals.(a) Use b

tekilochka [14]

We anticipate that the resulting aqueous solution will be basic.

<h3>What is the definition of a weak acid?</h3>

Weak acids are those that do not dissociate completely in solution. A weak acid is defined as any acid that is not a strong acid. A weak acid's strength is determined by how much it dissociates; the more it dissociates, the stronger the acid.

<h3>What exactly is a conjugate base?</h3>

A conjugate base is the base member, X-, of two compounds that transform into one another by gaining or losing a proton. In a chemical reaction, the conjugate base has the ability to gain or absorb a proton.

<h3>According to the given information:</h3>

Calcium propionate [Ca(CH₃CH₂COO)₂

We know that Calcium propionate dissolves completely in water.

So,

Ca(CH $_3$ CH $_2$ +COO) $_2$ →Ca $^2^+$ +2CH $_{3}$ CH $_2$ COO−