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Travka [436]
3 years ago
6

What is the percent concentration of a sodium fluoride solution made be dissolving 65.4 grams of sodium fluoride in 125.1 grams

of water?
Chemistry
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

34.33 %.

34.33 %.

34.33 %.

Explanation:

  • To calculate the mass percent or weight percent of a solution, you must divide the mass of the solute by the mass of the solution (both the solute and the solvent together) and then multiply by 100 to change it into percent.

<em>W% = [(W of solute NaF)/(W of solution)] x 100.</em>

<em></em>

W of solute NaF = 65.4 g.

W of solution = W of solute NaF + W of water = 65.4 g + 125.1 g = 190.5 g.

∴ W% = [(W of solute NaF)/(W of solution)] x 100 = [(65.4 g)/(190.5 g)] x 100 = 34.33 %.

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A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60
Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0
3 years ago
What prefix should be used to name a hydrocarbon that has a six-carbon parent chain?a.hex- b.meth- c.non- d.sept-
liberstina [14]
A. hex- Normally with 6, the prefix is hex-. For example a polygon having 6 sides is known as hexagon.
8 0
4 years ago
Determine the molecular formula for the compound with a molar mass of 46.08 g/mol and the following percent compostion:
kramer

Answer:

      \large\boxed{\large\boxed{CH_6N_2}}

Explanation:

<u><em>1. First determine the empirical formula.</em></u>

a) Base: 100 g of compound

             mass       atomic mass      number of moles

                g                g/mol                    mol

C           26.06            12.011             26.06/12.011   = 2.17

H           13.13              1.008              13.13/1.008    =  13.03

N           60.81             14.007            60.81/14.007 = 4.34

b) Divide every number of moles by the smallest number: 2.17

mass       number of moles        proportion

C                  2.17/2.17                         1

H               13.03/2.17                         6

N                4.34/2.17                          2

c) Empirical formula

      CH_6N_2

d) Mass of the empirical formula

      1\times 12.011g/mol6+6\times 1.008g/mol+2\times 14.007g/mol=46.07g/mol

<u><em>2. Molecular formula</em></u>

Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

                   CH_6N_2

6 0
3 years ago
HELP ASAP!!
Ksju [112]
109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0
3 years ago
Read 2 more answers
Migration is _______. a. the movement of organisms from a native location to a foreign location b. the movement of organisms fro
sergij07 [2.7K]

Answer:

A

Explanation:

4 0
2 years ago
Read 2 more answers
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