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Nikolay [14]
3 years ago
11

What is the length of ac if ab = 4x and bc = 2x+6?

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0
4x+2x+6 (which is ab plus bc)
6x+6 (the length of ac)
adoni [48]3 years ago
3 0
When m is. (1). 3 ... If AB<span> = 18, AC = 14, and </span>BC<span> = 10, what is the perimeter of quadrilateral ACRM? .... (</span>2<span>) </span>4x<span> + 3y = 10. (4) -</span>4x<span> + 3y = 26. I>~ b.</span>
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Can someone plz help me?
Oksanka [162]

Answer:

c

Step-by-step explanation:

c

7 0
3 years ago
SOMEBODY HELP MEEE!!!!
VladimirAG [237]
Solution= x=5
Alernative form= 21 x - 105= 0<span />
8 0
3 years ago
An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insu
ankoles [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?

Answer:

P( X' ∩ Y' ) = 0.205

Step-by-step explanation:

Let X is the event that the customer insures more than one car.

Let X' is the event that the customer insures exactly one car.

Let Y is the event that customer insures a sport car.

Let Y' is the event that customer insures not a sport car.

From the given information we have

70% of customers insure more than one car.

P(X) = 0.70

20% of customers insure a sports car.

P(Y) = 0.20

Of those customers who insure more than one car, 15% insure a sports car.

P(Y | X) = 0.15

We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

P( X' ∩ Y' ) = ?

Which can be found by

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

From the rules of probability we know that,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )    (Additive Law)

First, we have to find out P( X ∩ Y )

From the rules of probability we know that,

P( X ∩ Y ) = P(Y | X) × P(X)       (Multiplicative law)

P( X ∩ Y ) = 0.15 × 0.70

P( X ∩ Y ) = 0.105

So,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )

P( X ∪ Y ) = 0.70 + 0.20 - 0.105

P( X ∪ Y ) = 0.795

Finally,

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

P( X' ∩ Y' ) = 1 - 0.795

P( X' ∩ Y' ) = 0.205

Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

6 0
3 years ago
What is the solution of the equation?<br> -39.75 = 7.5m
kolezko [41]

Answer:

m = -5.3

Step-by-step explanation:

-39.75 = 7.5m

Divide both sides by 7.5 to get m alone

-39.75/7.5 = 7.5m/7.5

-5.3 = m

Hope this helps:)

6 0
3 years ago
Read 2 more answers
The domain of g(x) = 4x –12 is {2, 3, 6, 8}. What is the range
vlada-n [284]

Answer:

Range - {-4,0,12,20}

Step-by-step explanation:

Given that,

The function is :

g(x) = 4x –12

The domain of the function is {2, 3, 6, 8}.

g(2) = 4(2) –12 = -4

g(3) = 4(3) –12 = 0

g(6) = 4(6) –12 = 12

g(8) =  4(8) –12 = 20

Hence, the range of the function is {-4,0,12,20}.

7 0
2 years ago
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