Answer:
Astronomical Unit (AU). The definition of AU is the distance between the sun and the earth. Hopes this helps!
Explanation:
Answer:
A)Explanation:
Let object distance be u.
Image distance v = 1.06 - u
Focal length = 20 cm = .2 m
Applying lens formula
1 / v - 1 / u = 1 / f
1 /( 1.06-u) - 1 / u = 1 / .2
5 u² -3.3u - 1.06 =0
It will have two roots
u₁ = .1636 m, u₂ = .8964 m
B ) Magnification
= u = .1636m , v = .8964m
m = .8964 / .1636 = 5.48
C ) When u = .8964m ,v = .1634m
m = .1634 / .8964
=.182
Answer:
4.28 s
Explanation:
after two seconds (2 s) His friends is
d = 3.5 m/s x 2 s = 7 meter ahead.
in this state, a bicylist start from initial velocity vo = 0 m/s and accelerat 2.4 m/s²
then, when bicylist reach his friend
t friend = t bicyclist = t
d bicylist = d friend + d
-------
d friend = 3.5 . t
d bicylist = vo . t + ½ a t²
d friend + d = vo . t + ½ a t²
3.5 t + 7 = 0 . t + ½ . 2.4 . t²
3.5 t + 7 = 1.2 t²
0 = 1.2 t² - 3.5 t - 7
t = -1.363 and t = 4.28
take the positive one
Answer: 0.102m/s^2
Explanation:
velocity of ball = 6.15 m/s
Time taken for ball to roll = 1.00 minute
Convert 1.00 minute to seconds
(Since 60 seconds = 1 minute, the time taken for ball to roll = 60 seconds
Acceleration of the ball = ? (Let unknown value be Z)
Since acceleration is the rate of change of velocity per unit time
i.e Acceleration = Velocity / Time
Z = (6.15 m/s / 60 seconds)
Z = 0.1025m/s^2
Round Z to 3 significant digits (Z = 0.102m/s^2)
Thus, the acceleration of the ball is 0.102 metres per second square