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2 years ago

A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The

Physics

1 answer:

Vitek1552 [10]2 years ago

4 0

Answer: 0.102m/s^2

Explanation:

velocity of ball = 6.15 m/s

Time taken for ball to roll = 1.00 minute

Convert 1.00 minute to seconds

(Since 60 seconds = 1 minute, the time taken for ball to roll = 60 seconds

Acceleration of the ball = ? (Let unknown value be Z)

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = Velocity / Time

Z = (6.15 m/s / 60 seconds)

Z = 0.1025m/s^2

Round Z to 3 significant digits (Z = 0.102m/s^2)

Thus, the acceleration of the ball is 0.102 metres per second square

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lord [1]

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2 resistors of resistance 1000 ohm and 2000 ohm are joined in series with a 100V supply. A voltmeter of internal resistance 4000

Vadim26 [7]

<h2>The voltmeter reading will be 35.7 volt </h2>

Explanation:

The resistor 1000 ohm and 4000 ohm are connected in parallel .

Their combined resistance is supposed R₁

Thus $\frac{1}{R_1}$ = $\frac{1}{1000}$ + $\frac{1}{4000}$

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Because these are in series .

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here R is total resistance .

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2 years ago

imagine the first Olympic Games conducted on the moon in a specially designed dome. state and explain which sports would produce

Anastaziya [24]

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2 years ago

1. How would you expect an instantaneous acceleration vs. time graph to look for a cart moving with a constant

r-ruslan [8.4K]

Answer:

a=0 v = v₀ + a t

a=0 line is horizontal

Explanation:

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2, speed and relationship of a car is given by

v = v₀ + a t

where vo is the initial velocity, a is the acceleration and tel time

in this case I will calcograph velocity vs. time the constant acceleration is a straight line.

In general from the graph we can find the initial velocity with the cut at that x and the acceleration of the car with the slope

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3 years ago