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3 years ago

6

A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The

1 answer:

Vitek1552 [10]3 years ago

4 0

Answer: 0.102m/s^2

Explanation:

velocity of ball = 6.15 m/s

Time taken for ball to roll = 1.00 minute

Convert 1.00 minute to seconds

(Since 60 seconds = 1 minute, the time taken for ball to roll = 60 seconds

Acceleration of the ball = ? (Let unknown value be Z)

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = Velocity / Time

Z = (6.15 m/s / 60 seconds)

Z = 0.1025m/s^2

Round Z to 3 significant digits (Z = 0.102m/s^2)

Thus, the acceleration of the ball is 0.102 metres per second square

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lara [203]

Answer:

3.467 s

Explanation:

given,

distance , d = 49 mm = 0.049 m

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now,

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rejecting negative values

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now, time taken by the ball of Jerry

using equation of motion

$s = ut +\dfrac{1}{2}at^2$

taking downward as negative

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4.9 t² - 17 t - 0.049 = 0

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$t_2 = \dfrac{-(-17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}$

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rejecting negative values

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The magnitude of the magnetic field at a certain distance from a long, straight conductor is represented by B. What is the magni

den301095 [7]

Answer:

Option C is correct.

The magnitude of the field is reduced to half at twice the distance,

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3 years ago

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