A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The

Physics

1 answer:

Vitek1552 [10]2 years ago

4 0

Answer: 0.102m/s^2

Explanation:

velocity of ball = 6.15 m/s

Time taken for ball to roll = 1.00 minute

Convert 1.00 minute to seconds

(Since 60 seconds = 1 minute, the time taken for ball to roll = 60 seconds

Acceleration of the ball = ? (Let unknown value be Z)

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = Velocity / Time

Z = (6.15 m/s / 60 seconds)

Z = 0.1025m/s^2

Round Z to 3 significant digits (Z = 0.102m/s^2)

Thus, the acceleration of the ball is 0.102 metres per second square

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Initial $\rm KE$ of this arrow:

$\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}$ .