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ollegr [7]
3 years ago
9

Biology of awerness. Based on information in the articale, what is the most likely reason all organisms adapted to havea the tra

it of awarenes
Physics
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

Awareness was selected because it was beneficial to organisms in particular environments.

Explanation:

Based on the article, natural selection is a phenomenon that recognizes and allows traits that are useful to an organism and that would be favorable for it to be passed from one generation to another.

Natural selection marked awareness as a useful trait that would be beneficial for organisms because it helped them adapt well to the particular environments that they found themselves. For example, this ability helped an organism to be able to recognize where it could get food and light in its environment.

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What is the kinetic energy of an object moving 40m/s with a mass of 20kg?
Svet_ta [14]
KE = (1/2) (mass) (speed)²

KE = (1/2) (20 kg) (40 m/s)²

KE = (1/2) (20 kg) (1,600 m²/s²)

KE = (10 kg) (1,600 m²/s²)

KE = 16,000 Joules
7 0
3 years ago
How do I calculate the tension in the horizontal string?
matrenka [14]

ANSWER

T₂ = 10.19N

EXPLANATION

Given:

• The mass of the ball, m = 1.8kg

First, we draw the forces acting on the ball, adding the vertical and horizontal components of each one,

In this position, the ball is at rest, so, by Newton's second law of motion, for each direction we have,

\begin{gathered} T_{1y}-F_g=0_{}_{}_{} \\ T_2-T_{1x}=0 \end{gathered}

The components of the tension of the first string can be found considering that they form a right triangle, where the vector of the tension is the hypotenuse,

\begin{gathered} T_{1y}=T_1\cdot\cos 30\degree \\ T_{1x}=T_1\cdot\sin 30\degree \end{gathered}

We have to find the tension in the horizontal string, T₂, but first, we have to find the tension 1 using the first equation,

T_1\cos 30\degree-m\cdot g=0

Solve for T₁,

T_1=\frac{m\cdot g}{\cos30\degree}=\frac{1.8kg\cdot9.8m/s^2}{\cos 30\degree}\approx20.37N

Now, we use the second equation to find the tension in the horizontal string,

T_2-T_1\sin 30\degree=0

Solve for T₂,

T_2=T_1\sin 30\degree=20.37N\cdot\sin 30\degree\approx10.19N

Hence, the tension in the horizontal string is 10.19N, rounded to the nearest hundredth.

8 0
1 year ago
From this diagram which of the following can you conclude
Volgvan

Answer: A

Explanation:

I say opposites attract

3 0
3 years ago
Read 2 more answers
An 80-kgkg quarterback jumps straight up in the air right before throwing a 0.43-kgkg football horizontally at 15 m/sm/s . How f
vladimir1956 [14]

Answer:

V = 0.0806 m/s

Explanation:

given data

mass quarterback = 80 kg

mass football = 0.43 kg

velocity = 15 m/s

solution

we consider here momentum conservation is in horizontal direction.

so that here no initial momentum of the quarterback

so that final momentum of the system will be 0

so we can say

M(quarterback) ×  V = m(football) × v (football)   ........................1

put here value we get

80 ×  V  = 0.43  × 15

V = 0.0806 m/s

5 0
3 years ago
Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t
marin [14]

Answer:

Part a)

Q = 952 cal/day

Part b)

P = 46 Watt

Part c)

\Delta P = 54 W

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

m = 5000 kg

Q = 70,000 Cal

so we have energy required per kg

E = \frac{70,000}{5000}

E = 14 cal/kg

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

Q = 68 \times 14

Q = 952 cal/day

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

P = \frac{952 \times 4186}{24\times 3600}

P = 46 Watt

Part c)

resting power given in the book is

P' = 100 W

so this is less than the power given

\Delta P = 100 - 46

\Delta P = 54 W

6 0
3 years ago
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